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olasank [31]
4 years ago
14

Determine whether each table below models a linear, quadratic or exponential function

Mathematics
2 answers:
Natalka [10]4 years ago
7 0

Answer:

Linear   Quadratic   Exponential

Step-by-step explanation:

pantera1 [17]4 years ago
3 0

Answer:

First table models Linear, second quadratic and third one exponential functions.

Step-by-step explanation:

To find whether the given table models a linear function there should be a constant change in y values with the constant change in x values of the table.

We take the example of first table written as linear.

Here change in x values is

6 - 5 = 1

7 - 6 = 1

8 - 7 = 1

Similarly change in y values is

1 - 4 = -3

-2 - 1 = -3

-5 -(-2) = -3

There is a common difference in y values = -3

So the given table models linear function.

We take the second table.

For quadratic function with the constant change in x values, difference of difference in y values is constant.

Change in x - values

6 - 5 = 1

7 - 6 = 1

8 - 7 = 1

Difference in y values

1 - 0 = 1

4 - 1 = 3

9 - 4 = 5

Now difference in difference of y values

3 - 1  = 2

5 - 3 = 2

Here, difference in difference of y values is 2

So the given table models a quadratic equation.

Now we take the third table.

For exponential function in the form of f(x) = a(r)^{n} there should be a common ratio in the terms of y values.

\frac{\text{Second term of y}}{\text{First term of y }}= \frac{2}{1}=2

\frac{\text{Third term of y}}{\text{Second term of y }}= \frac{4}{2}=2

So there is a common ratio of 2 in each term.

Therefore, the given table models exponential equation.

First table models Linear, second quadratic and third one exponential functions.

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<h3><u>Step-by-step explanation:</u></h3>

let's rewrite this

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good luck my friend! hope this helped a lot! also, i found a website if you don't fully understand this, its called MathPapa, i didn't use it to work this out so my working might be different but it definitely helps me sometimes. for an equation like this, type it likes this: x+y=11; -x=-y-9

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