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3 years ago

What part of 40 is 16?

Mathematics

2 answers:

I am Lyosha [343]3 years ago

5 0

It is 40% 16 is 40% of 40

Anit [1.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

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In Rivertown High School, about 30% of the students buy a raffle ticket. Given that a student buys a raffle ticket, there is a 1

lesya [120]

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

Step-by-step explanation:

Step 1 :

Given,

The percentage of students buying the raffle ticket = 30%

The percentage that the student who bought the ticket wins the prize = 10%

We need to determined the probability that randomly selected student will buy a raffle ticket and win a prize.

Step 2 :

The probability that a student buys the raffle ticket = $\frac{30}{100} = \frac{3}{10}$

The probability that a student wins a prize = $\frac{10}{100}$ = $\frac{1}{10}$

The probability that a student who buys the ticket wins a price can be computed by taking the product of the above 2 probabilities.

= $\frac{3}{10}$ × $\frac{1}{10}$ = $\frac{3}{100}$ = 0.03

Step 3 :

Answer :

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

6 0

4 years ago

Miranda found out that there are 20 drops in 11 mL of medicine. She measured 15 drops of medicine into a measuring cup. How many

andreyandreev [35.5K]

Answer: Her measuring cup has 8.25 mL of medicine.

Step-by-step explanation:

As per given,

In 11 mL of medicine, there are 20 drops.

That means quantity in 1 drop = $\dfrac{11}{20}$ mL

Now , the quantity in 15 drops = 15 x quantity in 1 drop

= $15\times\dfrac{11}{20}$

$=\dfrac{33}{4}$

= 8.25 mL

Hence, her measuring cup has 8.25 mL of medicine.

6 0

3 years ago

The table above lists the frequencies of the C major key.

Talja [164]

Sj ebfbruejnxjjendnzjejnzzkijeskao

7 0

3 years ago

Consider the hypotheses below. Upper H 0: mu equals 50 Upper H 1: mu not equals 50 Given that x overbar equals 60, s equals 1

Neko [114]

Answer:

We conclude that $\mu\neq$ 50.

Step-by-step explanation:

We are given that x bar = 60, s = 12, n = 30, and alpha = 0.10

Also, Null Hypothesis, $H_0$ : $\mu$ = 50

Alternate Hypothesis, $H_1$ : $\mu$ $\neq$ 50

The test statistics we will use here is;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 60

s = sample standard deviation = 12

n = sample size = 30

So, Test statistics = $\frac{60-50}{\frac{12}{\sqrt{30} } }$ ~ $t_2_9$

= 4.564

At 10% significance level, t table gives critical value of 1.311 at 29 degree of freedom. Since our test statistics is more than the critical value as 4.564 > 1.311 so we have sufficient evidence to reject null hypothesis as our test statistics will fall in the rejection region.

P-value is given by, P( $t_2_9$ > 4.564) = less than 0.05% {using t table}

Here also, P-value is less than the significance level as 0.05% < 10% , so we will reject null hypothesis.

Therefore, we conclude that $\mu\neq$ 50.

7 0

3 years ago

A newsletter publisher believes that less than 58% of their readers own a Rolls Royce. For marketing purposes, a potential adver

quester [9]

Answer:

We don´t have at 95% of confidence, evidence to reject the publisher´s claim

Step-by-step explanation:

Population mean p₀ = 58 % or p₀ = 0,58

Hypothesis Test:

Null Hypothesis H₀ p = p₀

Alternative Hypothesis Hₐ p < p₀

For a significance level α = 0,05 means that CI = 95 % or CI = 0,95

z(c) = - 1,64

MOE = z(c)* √(p*q)/n

p - p₀ / √(p*q)/n = z(s)

And that z(s) is in the acceptance region

|z(s)| < |z(c)|

|z(s)| < 1,64

Then if that so we fail to reject H₀ . We don´t have evidence to reject the publisher´s claim

8 0

3 years ago