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3 years ago

8th grade math! BRAINLIEST will be given.

Mathematics

2 answers:

defon3 years ago

5 0

Answer:

48 ft

Step-by-step explanation:

trapecia [35]3 years ago

3 0

Answer:

x = 48

Step-by-step explanation:

14^2 + b^2 = 50^2

196 + b^2 = 2500

-196 -196

b^2 = 2304

√b^2 = √2304

b = 48

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SIMPLIFY. 6y^3(3 + 4y^2)

Hitman42 [59]

Answer:

18y^3 + 24y^5.

Step-by-step explanation:

6y^3(3 + 4y^2)

= 6*3 y^3 + 6*4 y^(3+2)

= 18y^3 + 24y^5.

5 0

3 years ago

plz help me i dont want the answer i just wanna know how to do it if i fail this test i fail my grade plz hep

hoa [83]

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2 years ago

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Find the percent of each number a. 50% of 46 b. 70% of 110

I am Lyosha [343]

A is 23 and the answer to b is 77

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3 years ago

(a) The lake behind a dam has an area of 55 hectares. When the gates in the dam are open, water flows out at a rate of 75 000 li

GaryK [48]

Answer:

a) The diagram shows a hemisphere with radius 6 cm.

Calculate the volume.

Give the units of your answer.

(The volume, V, of s sphere with radius r is V = 4/3πr³)

b). The diagram shows a prism ABCDEF.

The cross-section is a right angled triangle BCD. BD = 10 cm, BC = 5.2 cm and ED = 18 cm.

(i) a) Work out the volume of the Prism.

b) Calculate the angle BEC

c) The point G lies on the line ED and GD = 7 cm. Work out angle BGE

(Cambridge Assessment International Education. 0580/42, October/November 2019, Q 4)

(a)

(b)(i)a

(b)(i)b

(b)(i)c

2. The diagram shows a sector of a circle of radius 3.8 cm.

The arc length is 7.7 cm.

(i) Calculate the value of y.

(ii) Calculate the area of the sector.

(Cambridge Assessment International Education. 0580/42, May/June 2019, Q 8b)

(i)

(ii)

7 0

3 years ago

The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation

Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

Let X = weights of adult male birds of a certain species

So, X ~ Normal( $\mu=27.5,\sigma^{2} =1.1^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{ X-\mu}{\sigma } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 27.5 grams

$\sigma$ = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

Z score = $\frac{ X-\mu}{\sigma } }$ = $\frac{ 29.37-27.5}{1.1 } }$

= 1.7

4 0

3 years ago

8th grade math! BRAINLIEST will be given.​

8th grade math! BRAINLIEST will be given.