7 . 3
--- × ------
10. . 6
= 21
--------
60
= 7/20
V^2/(1-v^2/c^2)=R
v^2=R(1-v^2/c^2)
v^2=R-Rv^2/c^2
v^2-Rv^2/c^2=R
v^2(1-R/c^2)=R
v=sqrt(R/(1-R/c^2))
where R was original right side, dont forget plus minus
Answer:
Hope this helps :)
Step-by-step explanation:
8(x - 2) = 2x + 8
y+9 = -2(y + 1)
value of x in 8(x - 2) = 2x + 8
x=4
substitue
y+9=−2(y+1)
value of y y+9=−2(y+1)
y= - 11/3 or 3.66...
x=4
y=4 (I rounded 3.66)
0.3 if a higher number because anytime there is a negative that means the number is below zero. 0.3 is barley above 0. But -0.7 is below zero
1. x=5/2
2. x=3/4-3/4y
y belongs R
