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3 years ago

True or False

Mathematics

2 answers:

otez555 [7]3 years ago

8 0

The answer is true FYI

max2010maxim [7]3 years ago

8 0

The answer is true >.

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Any help would be great

Ad libitum [116K]

Answer:

88/57

Step-by-step explanation:

3 0

3 years ago

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Moreeeee freeeeee pointsssssssssssss have a great day

deff fn [24]

Answer:

Step-by-step explanation:

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3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago

BRAINLIEST TO CORRECT ANSWER!!!!

Vesna [10]

Answer:

$5,720.40

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

95i is a root of f(x)=x^2 +9025. find the other roots of f(x)

Alex_Xolod [135]

Answer:

Other root is -95i

Step-by-step explanation:

Here, Nature of roots of f(x) is imaginary roots.

Therefore, Roots are conjugate of each other.

Conjugate of x + yi is x - yi.

we get conjugate of 95i as -95i

Verification shows....

(x-95)(x+95i)=0

${x }^{2} - {95}^{2} {i}^{2} = 0 \\ {x }^{2} + {95}^{2} = 0 \\ {x }^{2} + 9025= 0 \\ f(x) = 0$

this, roots are -95i and 95i

5 0

4 years ago