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Inessa05 [86]
3 years ago
14

The table shows a pattern of exponents. Powers of 5 Value 5 cubed 125 5 squared 25 5 Superscript 1 5 5 Superscript 0 1 5 Supersc

ript negative 1 One-fifth 5 Superscript negative 2 StartFraction 1 Over 25 EndFraction What is the pattern as the exponents decrease? subtract 5 from the previous value subtract 100 from the previous value divide the previous value by 5 divide the previous value by 25
Mathematics
2 answers:
dimaraw [331]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Lunna [17]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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A gymnastics center charges a one-time membership fee of $35.75. In addition, the center charges its members $55.50 per class. W
Nitella [24]
I am pretty sure the correct answer is $146.75. Hope this helps!!!!!!!
7 0
3 years ago
Read 2 more answers
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
1 year ago
No links pls find the equation that represents the proportional relationship between in this graph
slamgirl [31]

Answer:

sjobciducbqpfhivñqrjivbñkqjvbñqjirv

4 0
2 years ago
What is the inverse of <br><br> X^2-2x+3
schepotkina [342]
So you have x, then you square it to get x^2, then you minus 2x, then +3
The inverse is going backwards so you -3 then +2x then square root x
So you get square root x + 2x -3
I'm pretty sure this is right, sorry if I'm wrong.
4 0
3 years ago
Choose a random number between 1 and 25. What is the probability that it is an even number
CaHeK987 [17]

Answer:

6/25

Step-by-step explanation:

its a probability  out of all the odd numbers such as 1,3,5,7,9,11,13,15,17,19,21,23,25

3 0
3 years ago
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