Entry control loop. Because a while loop can be infinite or not based on whether Boolean given is T or F. So we need to know the preexisting condition before we can solve it.
The answer is 2 frequencies.
A Full-Duplex QAM 64 K Modem uses two frequencies. One frequency is used for upstream and the other for downstream. A variety of common QAM forms are available and include, 16 QAM, 32 QAM, 64 QAM, and 256 QAM. For example, for domestic broadcast use, 64 and 256 QAM are used for cable modem and digital cable TV. The modulation scheme for this modem uses both amplitude and phase.
Answer:
For the first question I think it is chains
The second question.
The woman is suspicious at hotel doors have numbers so how could he have been confused
Explanation:
Answer:
double x = 2.5;
double y = -1.5;
int m = 18;
int n = 4;
string s = "Storm";
string t = "Watch";
The output of the expression "x + n*y - (x+n)*y" is "6.25".
and the output of expression "m/n + m%n" is "6".
Explanation:
for the first expression,
x + n*y - (x+n)*y ,put value of every variables in it.
=2.5+4*(-1.5)-(2.5+4)*(-1.5)
=2.5-6.0-(6.5*(-1.5)
=-3.5+9.75
=6.25
for the second expression,
m/n + m%n, put value of every variables in it.
=18/4 +18%4
=4+2 ("/ will give quotient and % will give remainder")
=6
