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3 years ago

What's 3 and 2 5ths plus 1 and 1 5ths

Mathematics

2 answers:

xeze [42]3 years ago

7 0

Its 4 an 3 5ths
because 3+1=4 and 2+1=3 and the donomenator is 5 so yeah

navik [9.2K]3 years ago

6 0

3 and 2/5 turns into 17/5
1 and 1/5 turns into 6/5
17+6= 23
23/5 simplifies to 4 and 3/5

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How to distribute 6 x(3+4) =56

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6x(3+4)56
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3 years ago

Jessica always uses the same ratio of green beads to blue beads when she makes necklaces. The graph shows these equivalent ratio

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3 years ago

Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).

QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

$\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}$

Using the section formula expressed as

$[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]$

In this case,

$\begin{gathered} m=1 \\ n=2 \end{gathered}$

where

$\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}$

Thus, by substitution, we have

$\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}$

Hence, the y-coordinate of the point P is

$0$

8 0

1 year ago

Helppppppppppppppppppppp!!!!!!!!!1

vitfil [10]

Answer: I need help too

Step-by-step explanation:

I think is -6

6 0

3 years ago

il63 [147K]

The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify $[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2$ and to find the value of s in $x^s$ .

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

$=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}$
Comparing with $x^S$
s = -16/3

Thus, the required value of the s = -16/3. None of these are correct.

Learn more about simplification here: brainly.com/question/12501526

#SPJ1

4 0

1 year ago