All categories

3 years ago

The width of a rectangle painting is 3 in. more than twice the height. A frame that is 2.5 in. wide goes around the painting.

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

5 0

A.
$A=(2h+8)(h+5)$

b.
If h = 12
$A=(24+8)(12+5)=(32)(17)=544$

c.
If h = 15
$A=(30+8)(15+5)=(38)(20)=760$

You might be interested in

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Strike441 [17]

I hope this is right

220.5 cubic feet

3 0

3 years ago

Solve for S P=4s Please answer!!!!

Karolina [17]

Answer:

Step-by-step explanation:

divide both sides of the equation by 4 to leave s by itself

6 0

3 years ago

Read 2 more answers

the ratio of peanut butter to cookie dough in a mixture is 1:5. Which of the following best describes the amount of peanut butte

arsen [322]

There is 5 times the amount of cookie dough to peanut butter
x:5x

6 0

3 years ago

Read 2 more answers

1kg-1/4-3/8= what is it please help

olga_2 [115]

Answer: it's either kg-5/8 or kg + -5/8

Step-by-step explanation:

4 0

2 years ago

The height of a tennis ball tossed into the air is modeled by h(x) = 40x â€" 16x 2, where x is elapsed time in seconds. During w

egoroff_w [7]

The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

Given that,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

We have to determine,

During what time interval will the tennis ball be at least 15 feet above the ground?

According to the question,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

Then,

When the tennis ball be at least 15 feet above the ground,

$h(x) = 15$

Substitute the value of h(x) in the equation,

$\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0$

Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,

$\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x = \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x = \dfrac{40\pm \sqrt{640}}{32}\\\\x = \dfrac{40 + 25.29}{32} \\\\x = \dfrac{40 + 25.29}{32} \ and \ x = \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45$

Hence, The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

For more details about Inequality refer to the link given below.

brainly.com/question/17177510

7 0

2 years ago