The answer would be : 0.
Hope this helps !
Photon
I also worked it out but I got -5/3
2(6p-5) ≥ 3(p-8) -1
12p-10 ≥ 3p-24-1
12p-10 ≥ 3p-25
12p-3p ≥ -25+10
9p ≥ -15
-15/9
P ≥ -5/3
Hi
5x²-x-4 = 0
Δ= (-1)² - 4*5*(-4)
Δ = 1 -4*-20
Δ = 1 +80
Δ = 81
√Δ= 9
as Δ ≥ 0 , so 2 solutions exist in R
S1 is : ( 1+9) /2*5 = 10/10 = 1
s2 = (1 -9)/2*5 = -8/10 = -4*2 /2*5 = -4/5
Corrects answers are A and D
Answer:
x = 5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2(3x - 7) = 16
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Division Property of Equality] Divide 2 on both sides: 3x - 7 = 8
- [Addition Property of Equality] Add 7 on both sides: 3x = 15
- [Division Property of Equality] Divide 3 on both sides: x = 5
