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Svetach [21]
3 years ago
13

I NEED THE ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 1/7-3(3/7x-2/7)

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

-  \frac {9x - 7}{7}

Step-by-step explanation:

Find the LCD and divide

melomori [17]3 years ago
6 0

Step-by-step explanation:

x in (-oo:+oo)

1/7-(3*((3/7)*x-(2/7))) = 0

1/7-3*((3/7)*x-2/7) = 0

1/7-3*(3/7*x-2/7) = 0

(-3*7*(3/7*x-2/7))/7+1/7 = 0

1-3*7*(3/7*x-2/7) = 0

7-9*x = 0

(7-9*x)/7 = 0

(7-9*x)/7 = 0 // * 7

7-9*x = 0

7-9*x = 0 // - 7

-9*x = -7 // : -9

x = -7/(-9)

x = 7/9

x = 7/9

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2 years ago
3/5 of the balls in a box are red . The rest are green and red .The ratio of the number of balls to the number of yellow balls i
just olya [345]

Answer:

Hello this question is impossible ask your teacher or find if you didnt make any mistake copying this HW.

Step-by-step explanation:

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6 0
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Read 2 more answers
Please help me!<br><br> Thank you
fgiga [73]

The required measures of the angle are given as,
∠JKL = 72°      ∠MLK = 108°      ∠JMK = 36°
∠MJL = 54°       ∠KNL = 90°

Given that.
The measure of the rhombus is given, we have to determine the measure of the angles,

<h3>What is angle?</h3>

orientation of one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as angle.

Here,
∠JKL= 2 × ∠JKM  = 72°
∠MLK = 180 - 2 × ∠JKM =  108°
∠JMK = ∠JKM = 36°
∠MJL = ∠MLK/2 =  54°
The diagonal of the rhombus bisect each other at an angle of 90°
So,
∠KNL = 90°

Thus, all the measure of the angles is shown above.

Learn more about Angles here:
brainly.com/question/13954458

#SPJ1

7 0
1 year ago
For what value of k, the zeroes of x2 + kx + 12 will differ by 1?
asambeis [7]

Let <em>a</em> and <em>b</em> be the zeroes of <em>x</em>² + <em>kx</em> + 12 such that |<em>a</em> - <em>b</em>| = 1.

By the factor theorem, we can write the quadratic in terms of its zeroes as

<em>x</em>² + <em>kx</em> + 12 = (<em>x</em> - <em>a</em>) (<em>x</em> - <em>b</em>)

Expand the right side and equate the coefficients:

<em>x</em>² + <em>kx</em> + 12 = <em>x</em>² - (<em>a</em> + <em>b</em>) <em>x</em> + <em>ab</em>

Then

<em>a</em> + <em>b</em> = -<em>k</em>

<em>ab</em> = 12

The condition that |<em>a</em> - <em>b</em>| = 1 has two cases, so without loss of generality assume <em>a</em> > <em>b</em>, so that |<em>a</em> - <em>b</em>| = <em>a</em> - <em>b</em>.

Then if <em>a</em> - <em>b</em> = 1, we get <em>b</em> = <em>a</em> - 1. Substitute this into the equations above and solve for <em>k</em> :

<em>a</em> + (<em>a</em> - 1) = -<em>k</em>   →   2<em>a</em> = 1 - <em>k</em>   →   <em>a</em> = (1 - <em>k</em>)/2

<em>a</em> (<em>a</em> - 1) = 12   →   (1 - <em>k</em>)/2 • ((1 - <em>k</em>)/2 - 1) = 12

→   (1 - <em>k</em>)²/4 - (1 - <em>k</em>)/2 = 12

→   (1 - <em>k</em>)² - 2 (1 - <em>k</em>) = 48

→   (1 - 2<em>k</em> + <em>k</em>²) - 2 (1 - <em>k</em>) = 48

→   <em>k</em>² - 1 = 48

→   <em>k</em>² = 49

→   <em>k</em> = ± √(49) = ±7

8 0
3 years ago
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