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Svetach [21]
3 years ago
13

I NEED THE ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 1/7-3(3/7x-2/7)

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

-  \frac {9x - 7}{7}

Step-by-step explanation:

Find the LCD and divide

melomori [17]3 years ago
6 0

Step-by-step explanation:

x in (-oo:+oo)

1/7-(3*((3/7)*x-(2/7))) = 0

1/7-3*((3/7)*x-2/7) = 0

1/7-3*(3/7*x-2/7) = 0

(-3*7*(3/7*x-2/7))/7+1/7 = 0

1-3*7*(3/7*x-2/7) = 0

7-9*x = 0

(7-9*x)/7 = 0

(7-9*x)/7 = 0 // * 7

7-9*x = 0

7-9*x = 0 // - 7

-9*x = -7 // : -9

x = -7/(-9)

x = 7/9

x = 7/9

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How do you solve this? r^2+32=12r
Andre45 [30]

Answer:

r = {-8, -4}

Step-by-step explanation:

Simplifying

r2 = -32 + -12r

Solving

r2 = -32 + -12r

Solving for variable 'r'.

Reorder the terms:

32 + 12r + r2 = -32 + -12r + 32 + 12r

Reorder the terms:

32 + 12r + r2 = -32 + 32 + -12r + 12r

Combine like terms: -32 + 32 = 0

32 + 12r + r2 = 0 + -12r + 12r

32 + 12r + r2 = -12r + 12r

Combine like terms: -12r + 12r = 0

32 + 12r + r2 = 0

Factor a trinomial.

(8 + r)(4 + r) = 0

Subproblem 1

Set the factor '(8 + r)' equal to zero and attempt to solve:

Simplifying

8 + r = 0

Solving

8 + r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + r = 0 + -8

Combine like terms: 8 + -8 = 0

0 + r = 0 + -8

r = 0 + -8

Combine like terms: 0 + -8 = -8

r = -8

Simplifying

r = -8

Subproblem 2

Set the factor '(4 + r)' equal to zero and attempt to solve:

Simplifying

4 + r = 0

Solving

4 + r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + r = 0 + -4

Combine like terms: 4 + -4 = 0

0 + r = 0 + -4

r = 0 + -4

Combine like terms: 0 + -4 = -4

r = -4

Simplifying

r = -4

Solution

r = {-8, -4}

3 0
3 years ago
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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Answer:

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Step-by-step explanation:

151.34 ÷ 658 × 100

hope this helps

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6 0
2 years ago
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Find the value of x in the isosceles triangle shown below.
natima [27]

Answer:

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8 0
3 years ago
Is y=3x-5 and 6x=2y+10 a solution
iVinArrow [24]
Y=3x-5
y-3x=-5
Times 2 from both side
y(2)-3x(2)=-5(2)
2y-6x=-10
Times negative from both side
(-)2y-6x(-)=(-)-10
-2y+6x=10
or
6x-2y=10


6x=2y+10
6x-2y=10
Furthermore, we see that both equation have the same 6x-2y=10 which means that both of them have infinity solutions, not a solution. Hope it help!
5 0
3 years ago
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