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astra-53 [7]
2 years ago
11

A line with a slope of 1 passes through the point (18, 15). What is its equation in slope-intercept form? Write your answer usin

g integers, proper fractions, and improper fractions in simplest form.​
Mathematics
1 answer:
Setler79 [48]2 years ago
4 0

Answer:

y = x - 13

Step-by-step explanation:

Given parameters:

  Slope of the line  =  1

  Coordinate = (18, 15)

Unknown:

Equation of the line in slope-intercept format = ?

Solution:

The equation of a line is expressed as;

         y  =  mx + c

where y and x are the coordinates

          m is the slope

          c is the y-intercept

Now, sine x = 18 and y = 5, let us find c;

        5 = 1(18) + c

      5 = 18 + c

       c = -13;

 The equation of the line is;

       y  = 1(x) + (-13)

       y = x - 13

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I guess the function is f(x)=9-x^{2/3}. Then f(-27)=0 and f(27)=0.

The derivative is f'(x)=-\dfrac23 x^{-1/3}, but there is no c such that

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This doesn't contradict Rolle's theorem because f'(0) does not exists. In other words, f is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")

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You borrowed $25 from your friend. You paid him back in full after 6 months. He charged $2 for interest. What was the annual sim
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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the cir
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The statements which are correct about the equation of circle x^{2} +y^{2}-2x-8=0 are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is x^{2} +y^{2} =9.

Given the equation of circle be x^{2} +y^{2}-2x-8=0.

We are required to find the appropriate statements related to the equation x^{2} +y^{2}-2x-8=0.

x^{2} +y^{2}-2x-8=0 can be written as under:

x^{2} +y^{2} -2x+1-9=0

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From the comparison of both the equations we get that radius is 3 units.

From the equation point will be (1,0). It is on the x axis.

Hence the statements which are correct about the equation of circle x^{2} +y^{2}-2x-8=0 are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is x^{2} +y^{2} =9.

Learn more about radius at brainly.com/question/24375372

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