Answer:
false
Step-by-step explanation:
any line segment or distance has only one midpoint.
there is only one middle to everything.
how would that look like, if something had 2 middles ?
then they would not be a middle, and the middle between these 2 middles would then be the real middle ...
Answer:
A series of prime numbers starting with 9?
They are both proportional. 1:4 and 1:15
It starts with family starts their holiday journey it's a book read it it will be fun
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
---------------------
So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
---------------------
<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
