From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)
The answer is:
<span>D. Minimum at (2, 3)</span>
0.5 is the decimal equivalent to 1/2
A= 1,3
B= 5,5
C= 6,1
Here you go
Answer:
The equation is y=2x + 2
Step-by-step explanation:
4x+2y=7
2y=-4x+7
y=-2x+7/2
Hence, the gradient =-2
Note that: parallel lines share the same gradient
sub m(gradient)=-2 and the point (1,0) into y=mx+c
0=-2(1)+c
c=2
Therefore, the equation in the form of y=mx+c is y=-2x+2
