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AVprozaik [17]
3 years ago
13

HELP ASAP!!!!!!!! what is the unit rate expressed in price per pound

Mathematics
1 answer:
maxonik [38]3 years ago
5 0

Answer:

$0.80

Step-by-step explanation:

You have to divide 24 by 30 to find the price per pound

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Kaden works 5 days. The median number of hours he works is 3. The mean number of hours he works is 4.
alisha [4.7K]

Answer:

(a) 1, 2, 3, 6, 8

Step-by-step explanation:

Given

Median = 3

Mean = 4

Required

The sequence of hours worked each day

<em>See attachment for options</em>

From the question, we understand that:

Median = 3

This means that, the middle number is 3 (when sorted)

So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively

Next, is to determine the mean of (a) and (d)

The mean of a data is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

(a)

\bar x = \frac{1+ 2+ 3+ 6+ 8}{5}

\bar x = \frac{20}{5}

\bar x = 4

(d)

\bar x = \frac{1+ 2+ 3+ 4+ 5}{5}

\bar x = \frac{15}{5}

\bar x = 3

Option (a) is true, because it has:

Median = 3

Mean = 4

7 0
3 years ago
2. An aquarium has display tanks that each
Sindrei [870]

Answer:

1050

Step-by-step explanation:

175*6=1050

3 0
3 years ago
Read 2 more answers
Hi what is the answer for b please
Ray Of Light [21]

E = 352.50 euro × 1 pound / 1.41 euro = 250.00 pounds

J = 39856 yen × 1 pound / 188 yen = 212.00 pounds

a) Japan is cheaper

b) 250 - 212 = 38 pounds cheaper

7 0
3 years ago
Jessica rides the bus 8% miles each day.how many miles does she ride in 10 days?
liq [111]

Answer:

80 miles

Step-by-step explanation:

3 0
3 years ago
What is the value of k in the equation StartFraction k Over 3 EndFraction minus 5 = 34?
12345 [234]

\huge\text{$k=\boxed{117}$}

\displaystyle\frac{k}{3}-5=34

To find the value of k, we need to isolate it on one side of the equation. Add 5 to both sides of the equation, then multiply both sides of the equation by 3.

\displaystyle\begin{aligned}\frac{k}{3}-5+5&=34+5\\\frac{k}{3}&=39\\\frac{k}{3}*3&=39*3\\k&=\boxed{117}\end{aligned}

4 0
3 years ago
Read 2 more answers
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