Question

Factor completely (3x^2−12x)(x^2−2x+1)=

Answer 1

Answer:

3x^4-18x^3+27x^2-12x

Step-by-step explanation:

Multiply the second paréntesis for each term of the first parentage

3x^2×(x^2-2x+1)-12x×(x^2-2x+1)

Multiply parentage by 3x^2

3x^4-6x^3+3x^2-12x×(x^2-2x+1)

Multiply the parentage by -12x

3x^4-6x^3+3x^2-12x^3+24x^2-12x

Group similar terms

3x^4-18x^3+27x^2-12x