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Marat540 [252]
3 years ago
14

What is the answer to the problem??

Mathematics
1 answer:
Archy [21]3 years ago
6 0
You would divide the two numbers to get 54
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9/11 ÷ 5/11 = a b/c =
stepan [7]

9/11 / 5/11

= 9/11 * 11/5

= 9/5

= 1 4/5

5 0
3 years ago
Read 2 more answers
What is 3 = -2v − v<br><br> v=
horsena [70]

Answer:

-1 =v

Step-by-step explanation:

3 = -2v − v

Combine like terms

3 = -3v

Divide each side by -3

3/-3 = -3v/-3

-1 =v

8 0
3 years ago
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128.09 to the nearest tenth
vaieri [72.5K]

Answer:

128.1

Step-by-step explanation:

Since this is rounding to the nearest tenth , we look at the first number after the decimal place it's 0 so we look at the second number after the decimal place which is 9 , this rounds 0 up to 1

8 0
3 years ago
3 tenths + 4 Tenths = __0.7____ tenths
vovangra [49]

Answer:

7 tenths

Step-by-step explanation:

3 tenths + 4 tenths = 3/10 + 4/10 = 0.3 + 0.4 = 0.7

= 7 tenths

6 0
3 years ago
Task: Nonpermissible Values for Rational Expressions [30 points] Write a rational expression that has the nonpermissible values
igor_vitrenko [27]

Answer:

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of x, the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

f(x) = \frac{p(x)}{q(x)} (1)

Then, the factorized form of q(x) must be:

q(x) = x\cdot (x-17) (2)

If we know that p(x) = 4, then the rational expression is:

f(x) = \frac{4}{x\cdot (x-17)} (3)

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

8 0
3 years ago
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