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kozerog [31]
3 years ago
9

SOMEONE PLEASE ANSWER WITH WORK I WILL GOVE BRAINLIEST

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer: what grade are you in

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Step-by-step explanation:

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Find all the zeros of the equation. -3x^4+27x^2+1200=0 PLEASE HELP and show work
asambeis [7]

Answer: x=−5 or x=5


Step-by-step explanation:

−3x4+27x2+1200=0

Step 1: Factor left side of equation.

−3(x2+16)(x+5)(x−5)=0

Step 2: Set factors equal to 0.

x2+16=0 or x+5=0 or x−5=0

x=−5 or x=5


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3 years ago
Find the mode for data set 3, 2, 8, 5, 1, 4, 4, 3, 4, 5, ​
Pepsi [2]

Answer:

Mode is 4

Step-by-step explanation:

3 0
3 years ago
Evaluate without using a mathematical table<br>1000(√0.0128÷200) <br>​
lapo4ka [179]

Answer:

0.5656854249

Step-by-step explanation:

1000(0.0128/200)

1000(0.11314/200)

1000(0.0005656854)

=0.5656854249

5 0
2 years ago
X + 3 = 11 A. x = 11 B. x = 23 C. x = 14 D. x = 8
lisov135 [29]

Answer:

8 (D)

Step-by-step explanation:

11 - 3 = x

11-3 = 8

hope this helps

3 0
3 years ago
Read 2 more answers
The mean incubation time of fertilized eggs is 23 days. Suppose the incubation times are approximately normally distributed with
Anna007 [38]

Answer: the incubation time that separates the bottom 2.5​% from the rest of the incubation times is 24.96 days.

Step-by-step explanation:

Suppose the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = incubation times.

µ = mean time

σ = standard deviation

From the information given,

µ = 23 days

σ = 1 day

The probability value for the incubation time that separates the bottom 2.5​% from the rest of the incubation times would be (1 - 2.5/100) = (1 - 0.025) = 0.975

Looking at the normal distribution table, the z score corresponding to the probability value is 1.96

Therefore,

1.96 = (x - 23)/1

x = 1.96 + 23

x = 24.96

3 0
3 years ago
Read 2 more answers
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