Answer:
12(2y^2)^1/2
Step-by-step explanation:
you could just do trial and error if your calculator can do cube root
Step-by-step explanation:
I am not sure, if something else is missing.
but given that one chart we can say that Craig had 2 fastest throws.
they were in the category 70-75 mph.
but we cannot say precisely which one was faster, and how fast it went.
it is also not clear what is the categorization of a border element (e.g. with an exact speed of 60 mph - is it in the 55-60 or in the 60-65 category ? or both ?).
I assume the upper limit of each interval is included, and the lower limit is excluded.
under this assumption we can say the fastest pitch was faster than 70 mph but slower than or equal to 75 mph.
Answer:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Step-by-step explanation:
Hello!
We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.
We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:
- The radial coordinate which is often denoted by r.
- The angular coordinate by θ.
So we need to find r and θ. So we know that:
(1)
x = rcos(θ) (2)
x = rsin(θ) (3)
From the statement we know that (x, y) = (3, -3).
Using the equation (1) we find that:

Using the equations (2) and (3) we find that:
3 = rcos(θ)
-3 = rsin(θ)
Solving the system of equations:
θ= -45
Then:
r = 3\sqrt{2}[/tex]
θ= -45 or 315
Notice that there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.
So, the solution is:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
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