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mario62 [17]
3 years ago
11

A girl scout was selling boxes of cookies. In a month, she sold both boxes of chocolate chip cookies ($1.25 each) and boxes of p

lain cookies ($0.75 each). Altogether, she sold 1585 boxes for a combined value of $1588.75. How many boxes of plain cookies did she sell?
Mathematics
2 answers:
nydimaria [60]3 years ago
8 0

Answer:

785

Step-by-step explanation:

Let the number of the boxes of chocolate chip cookies sold by her = x

Let the number of boxes of plain cookies sold by her = y

So, x + y = 1585 --------------------1

Price of 1 unit of chocolate chip box = $1.25

Price of 1 unit of plain cookie box = $0.75

Thus,

1.25x + 0.75y = 1588.75 -----------------2

Solving 1 and 2 as:

y = 1585 - x

Putting in 2 , we get that:

1.25x + 0.75(1585 - x) = 1588.75

x = 800

y = 785

Plain boxes = 785

Katena32 [7]3 years ago
3 0

Answer:

Number of plain cookie boxes sold = 785 boxes

Step-by-step explanation:

Given: Cost of a chocolate chip cookie box = $1.25

Cost of a plain cookie box = $0.75

Total number of boxes sold = 1585

Total cost of the sold boxes = $1588.75

Let, number of plain cookie boxes sold = x

Number of chocolate chip cookie boxes sold = 1585 - x

So,

Total cost = total cost of the sold plain cookie boxes + total cost of the sold chocolate chip cookie boxes

$1588.75 = x ($0.75) + (1585 - x) ($1.25)

1588.75 = 0.75 x + 1981.25 - 1.25 x

0.5 x = 392.5

Therefore,

<u>Number of plain cookie boxes sold: x = 392.5 ÷ 0.5 = 785 boxes</u>

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0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

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In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

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