Question

Find a cubic function with the given zeros.

Answer 1

The cubic function is $f(x)=x^3+3x^2-46x-168$

Option D is correct

Step-by-step explanation:

We need to find the cubic function with the given zeros -6,7,-4

If -6,7,-4 are zeros of the function then:

x=-6, x=7 and x=-4

=> x+6=0,x-7=0 and x+4=0

Multiplying these terms to find the cubic function:

(x+6)(x-7)(x+4)

Solving:

$(x+6)(x-7)(x+4)\\=(x+6)(x(x+4)-7(x+4))\\=(x+6)(x^2+4x-7x-28)\\=(x+6)(x^2-3x-28)\\=x(x^2-3x-28)+6(x^2-3x-28)\\=x^3-3x^2-28x+6x^2-18x-168\\Combining\,\,like\,\,terms:\\=x^3-3x^2+6x^2-28x-18x-168\\=x^3+3x^2-46x-168$

So, the cubic function is $f(x)=x^3+3x^2-46x-168$

Option D is correct

Keywords: cubic function

Learn more about cubic function at:

• brainly.com/question/1464739
• brainly.com/question/1560475
• brainly.com/question/2568692

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