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In ∆ ABC and ∆ADC
AB=AD
AC=AC(common side)
BC=DC
So, ∆ABC and ∆ADC are congruent triangles,
so, m<ABC= m<ADC(corresponding angles of the congruent triangles)
x= 97°
In ∆ ABC and ∆ADC
AB=AD
AC=AC(common side)
BC=DC
So, ∆ABC and ∆ADC are congruent triangles,
so, m<ABC= m<ADC(corresponding angles of the congruent triangles)
x= 97°