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erastova [34]
4 years ago
12

Tell me the answer ​

Mathematics
1 answer:
romanna [79]4 years ago
5 0
Show a picture or type the question so we can give you an answer please.
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AABC is a right triangle. If AC = 15 and BC = 17, find AB.
Schach [20]

Answer:

AC=15

BC=17

AB=?

According to Pythagore's Theorem: AB² + AC² = BC².

AB² = BC² - AC²

= (17)² - (15)²

= 289 - 225

AB² = 64

AB = √(64)

= 8.

So AB = 8.

4 0
4 years ago
The ratio of potatoes to turnips is 1:1 if there are 473 potatoes how many turnips are there
navik [9.2K]

Answer:

There would be 473 turnips.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3 times a certain number n is added to 6, the sum is 20 more than the original
Vikentia [17]

Answer:

n = 5.33→

Step-by-step explanation:

4 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
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⚠️ILL GIVE BRANLIEST!
SSSSS [86.1K]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
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