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3 years ago

6) You flip a coin twice. The first flip lands

Mathematics

1 answer:

slavikrds [6]3 years ago

8 0

Answer:

independent, 1/4

Step-by-step explanation:

The events are independent because what occurs on the first flip does not affect the second flip

P(heads) = 1/2

P(heads, heads) = 1/2*1/2 = 1/4

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if an amount of $5,000 is deposited into a savings account at an annual interest rate of 5%, compounded monthly, what is the val

Ugo [173]

Answer:

$8,240

Step-by-step explanation:

We are given that,

Principle amount in the savings account, P = $5,000.

Rate of interest, r = 5% = 0.05

Time period, t = 10

Also, the interest is compounded monthly, n = 12

As, we now that the value of the investment is given by $P(1+\frac{r}{n})^{nt}$

Thus, we have,

Investment Value = $5000(1+\frac{0.05}{12})^{12\times 10}$

i.e. Investment Value = $5000(1+\frac{0.05}{12})^{12\times 10}$

i.e. Investment Value = $5000(1+0.00417)^{120}$

i.e. Investment Value = $5000\times 1.648$

i.e. Investment Value = $8,240

Hence, the investment amount after 10 years is $8,240.

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3 years ago

74 m A 70 m b What is the length of the missing leg? b = meters Submit

igor_vitrenko [27]

I’m a little confused by the question and the problem, is there a picture of the problem you could add?

5 0

3 years ago

Given a right circular cone a plane that intersects the cone (not at the vertex) and is parallel to its edge will always result

arlik [135]

Answer on APEX is true

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3 years ago

Read 2 more answers

What is the integer of-2

Gnom [1K]

Answer:

-2

Step-by-step explanation:

The integer of - 2 is - 2 only as integers can be positive and negative whole numbers

4 0

3 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: