<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
z= - 5
√
38
Step-by-step explanation:
take the root of both sides
or
you can factor each set and make them equal to zero
Answer:
1 is Answer.
Step-by-step explanation
= 
As we know that ω²+ω+1=0
Thus putting in above equation, we get
= 
Rearranging and simplifying:
= 
=
= 
= 1 Answer
Answer:
there isnt enough evidence to colclude an answer
Step-by-step explanation:
Answer:
y= -4 x+3
Step-by-step explanation: A(1, -1)
the equation is y - y (A)=m*( x-x(A) )
y-(-1)=-4(x-1)
y+1=-4x+4
y= -4x+4-1
y=-4x+3
y=-4x+4-1
