Lets approach this problem differently
15 gallons ....you drive ......330 miles lets divide both numbers by 15 to find out how much you can go with 1 gallon
1 gallon..... you drive.....330/15=22
you car goes 22 miles per 1 gallon
if you put 20 gallons
20*22=440 miles
Y = ln {[sin(x)]^2}
use the chain rule
y' = 1 /[sin(x)]^2 * 2sin(x)*cos(x) = 2cos(x) / sin(x) = 2 cot(x)
Answer: 2 cot(x)
Answer:
1 hour and 53 minutes
Step-by-step explanation:
Your welcome
I'm assuming this is 0.1666666...
Which in that case is 1/6.
(Just from memory)
To do 0.161616161616...
First, assign 0.161616... a variable, say it's x.
Now say 100x, what is it.
16.1616161616...
Now subtract x from 100x.
16.161616161616... - 0.16161616...
Or, 99x
99x = 16 in this case right now
Divide both sides by 99
x = 16/99
So it really depends what's repeating, it's either 1/6 or 16/99.
Answer:
1. Sine θ = 1/3
2. Cos θ = 2√2 / 3
3. Tan θ = √2 / 4
4. Cosec θ = 3
5. Sec θ = 3√2 / 4
6. Cot θ = 2√2
Step-by-step explanation:
We'll begin by determining the adjacent. This can be obtained as follow:
Hypothenus (Hypo) = 9
Opposite (Opp) = 3
Adjacent (Adj) =?
Hypo² = Adj² + Opp²
9² = Adj² + 3²
81 = Adj² + 9
81 – 9 = Adj²
72 = Adj²
Take the square root of both side
Adj = √72
Adj = 6√2
Finally, we shall determine six trigonometric functions of the angle θ. This Can be obtained as follow:
1. Determination of Sine θ
Hypothenus = 9
Opposite = 3
Sine θ =?
Sine θ = Opposite / Hypothenus
Sine θ = 3/9
Sine θ = 1/3
2. Determination of Cos θ
Adjacent = 6√2
Hypothenus = 9
Cos θ =?
Cos θ = Adjacent / Hypothenus
Cos θ = 6√2 / 9
Cos θ = 2√2 / 3
3. Determination of Tan θ
Opposite = 3
Adjacent = 6√2
Tan θ =?
Tan θ = Opposite / Adjacent
Tan θ = 3 / 6√2
Tan θ = 1 / 2√2
Rationalise
(1 / 2√2) × (2√2 /2√2)
= 2√2 / 4×2
Tan θ = √2 / 4
4. Determination of Cosec θ
Sine θ = 1/3
Cosec θ =?
Cosec θ = 1 / Sine θ
Cosec θ = 1 ÷ 1/3
Cosec θ = 1 × 3/1
Cosec θ = 3
5. Determination of sec θ
Cos θ = 2√2 / 3
Sec θ =?
Sec θ = 1 / Cos θ
Sec θ = 1 ÷ 2√2 / 3
Sec θ = 1 × 3 / 2√2
Sec θ = 3 / 2√2
Rationalise
= (3 / 2√2) × (2√2 / 2√2)
= 3 × 2√2 / 4×2
Sec θ = 3√2 / 4
6. Determination of Cot θ
Tan θ = √2 / 4
Cot θ =?
Cot θ = 1 / Tan θ
Cot θ = 1 ÷ √2 / 4
Cot θ = 1 × 4 / √2
Cot θ = 4 / √2
Rationalise
= (4 / √2) × (√2 / √2)
= 4√2 / 2
Cot θ = 2√2
