Answer:
0.8
Step-by-step explanation:
0.3t = 0.24
divide both sides by 0.3
t = 0.8
The answer is <span>B. 196 π mi2
</span>
(1) Find radius r:
The area of the circle is:
A = r²π
A = 49π mi²
49π = r²π
49 = r²
r = √49 = 7 mi
(2) Find the surface area of the sphere.
The surface area of the sphere is:
A = 4πr²
r = 7 mi
A = 4π * 7²
A = 4π * 49
A = 196π mi²
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Let the number be x.
6x-20=94
6x=114
x=19
