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ycow [4]
3 years ago
15

- One night a theater sold 548 movie tickets. An adult's ticket costs $6.50 and a child's ticket cost $3.50.

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Let X= each ticket for adults and Y= each ticket for kids

x+y=548

6.50x+3.50y=2881

subtract x from each side leaving you with y= -x+548

Plug in for Y

6.50x+3.50(-x+548)=2881

6.50x - 3.50x + 1918= 2881

3x+1918=2881 ....subtract

3x=963 .....divide by 3

X= 321 tickets for adults

321+y=548 ...subtract 321

Y=227 childrens tickets

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<span>5° above zero</span>
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agasfer [191]

Answer: <em><u>it is =4176000000000000</u></em>

Step-by-step explanation:

(2.9)(100000)(7.2)(10^2)

5(10^−8)

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5(10^−8)

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GIVING BRAINLIEST TO CORRECT ANSWER
Ksju [112]
The answer is D. The most customers were at 12pm on both days.
6 0
3 years ago
Read 2 more answers
In the movie industry, the release date of a film is very important (this is true of any good, but let's consider movies for now
Alborosie
(a) Profit equation
Profit = revenue - cost
unit profit = revenue per unit - cost per unit = 16-7.3=8.7
profit
p(x) = (unit profit)*x=8.7x

(b) profit over time
sales,
x(t) = 1000 * (100 * (ln(t^2+87)+48.8)
=100000 ln(t^2+0.87)+48800

profit,
P(t)
=p(x(t))-5200000
=p(100000 ln(t^2+0.87)+48800)-5200000
=8.7(100000 ln(t^2+0.87)+48800)-5200000
=870000*ln((t^2+0.87))-4775440

(c)
Break even quantity is when p(x)-5200000=0, 
solving,
8.7x-5200000=0 =>
x=5200000/8.7
=597701.1
=597702 (rounded to next integer)

(d)
Time t to reach break even is when
P(t)=0
or
solve for t in 
870000*ln((t^2+0.87))-4775440=0
ln(t^2+0.87)=4775440/870000=5.489
raise powers to base of e
t^2+0.87=e^(5.489)=242.018
t=sqrt(242.018-0.87)=15.53 months.
7 0
3 years ago
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