You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)
Answer: I'm not entirely sure, but maybe 1/x^2?
Answer:
11.9
Step-by-step explanation:
-11.9/-1
so the both cancel out each other
so it will just be 11.9 ,since it is -1
You need to use a system of equations with 2 variables
where x= # of paintbrushes bought
and y= # of paint units bought
the first equation would be
.95x+.99y=4.87
Usually there is more information given in these problems so that you can make the second equation. Did the problem say how many total items were bought or anything else because given this information you cannot make a second equation and therefore cannot solve for both variables. Also, the wording is unclear, did she spend 4.87 on just paintbrushes or both brushes and paint.
X + y= 30
.05x + .10y= 1.65
n + d = 30
5n + 10d = 165
-5n - 5d = -150
5n + 10d = 165
5d = 15
d = 3 dimes
n + 3 = 30
n= 27 nickels
