Two times the smaller of two consecutive integers is equal to 2 more than the larger. What is the LARGER integer?
1 answer:
Answer:
The larger integer is .
Step-by-step explanation:
Given: Two times the smaller of two consecutive integers is equal to more than the larger.
To find: The larger integer.
Solution:
Let the two consecutive integers be and
, where the smaller integer is
and larger integer is
.
Now, according to question.
Two times the smaller integer
more than the larger integer.
So, the smaller integer is , and the larger integer is
Hence, the larger integer is
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Step-by-step explanation:
This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a
The formula for the foci of the vertical ellipse is
(h,k+c) and (h,k-c).
where c is
Our center (h,k) is (2, -5)
Here a^2 is 9, b^2 is 4.
So our foci is
and
You did not provide a list of expressions to select from.
Let A = area
Let w = width
Let (w + 5) = length
A = (w + 5)w
Let A = area
Let w = width
Let (w + 5) = length
A = (w + 5)w
Answer:
0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected
Step-by-step explanation:
To solve this question, we have to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central limit theorem:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error
In this problem, we have that:
The standard deviation is the square root of the variance. So
What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected
Either it differs by 104 or less dollars, or it differs by more than 104 dollars. The sum of the probabilities of these events is 100. I am going to find the probability that it differs by 104 or less dollars first.
Probability that it differs by 104 or less dollars first.
pvalue of Z when X = 16127 + 104 = 16231 subtracted by the pvalue of Z when X = 16127 - 104 = 16023. So
X = 16231
By the Central Limit Theorem
has a pvalue of 0.9970
X = 16023
has a pvalue of 0.0030
0.9970 - 0.0030 = 0.9940
99.40% probability that it differs by 104 or less.
What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected
p + 99.40 = 100
p = 0.60
0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected