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Free_Kalibri [48]
3 years ago
7

Two times the smaller of two consecutive integers is equal to 2 more than the larger. What is the LARGER integer?

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

The larger integer is 4.

Step-by-step explanation:

Given: Two times the smaller of two consecutive integers is equal to 2 more than the larger.

To find: The larger integer.

Solution:

Let the two consecutive integers be x and x+1,  where the smaller integer is x and larger integer is x+1.

Now, according to question.

Two times the smaller integer = 2 more than the larger integer.

\implies 2x=x+1+2

\implies 2x-x=3

\implies x=3

So, the smaller integer is 3, and the larger integer is 3+1=4.

Hence, the larger integer is 4.

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Which is the greatest rational number?<br><br> A. 3 2/7<br> B. 3 1/4<br> C. 3.31<br> D. 3.36
lana [24]

Answer:

D.

Step-by-step explanation:

3 1/4 = 3.25

3 2/7 = 3.29

3.29>3.25

3.31>3.29

3.36>3.31

so the answer is D.

4 0
3 years ago
Which expression is the product of (x + 4i)(x − 4i)(x + 4)?
Sophie [7]
Answer= x³+4x²+16x+64

Expand the following:(x + 4 i) (x - 4 i) (x + 4)
(x - 4 i) (x + 4) = (x) (x) + (x) (4) + (-4 i) (x) + (-4 i) (4) = x^2 + 4 x - 4 i x - 16 i = -16 i + (4 - 4 i) x + x^2:
-16 i + (-4 i + 4) x + x^2 (4 i + x)
 | | | | x | + | 4 i
 | | x^2 | + | (4 - 4 i) x | - | 16 i
 | | | | (-16 i) x | + | 64
 | | (4 - 4 i) x^2 | + | (16 + 16 i) x | + | 0
x^3 | + | (4 i) x^2 | + | 0 | + | 0
x^3 | + | 4 x^2 | + | 16 x | + | 64:
Answer: x^3 + 4 x^2 + 16 x + 64
7 0
3 years ago
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Flura [38]

Answer:

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Step-by-step explanation: I just kinda guessed and got it right.

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Rewrite using the distributive property then solve using gcf. 5(4+3)
Vitek1552 [10]

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Convert 0.96 to a percent: 0.96 = 96%

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The house loses 4% of it's value every year.

5 0
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