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Tema [17]
3 years ago
13

It takes 32 minutes for 3 people to paint 4 walls. How many minutes does it take 4 people to paint 7 walls?

Mathematics
2 answers:
drek231 [11]3 years ago
7 0

Answer:

52 minutes because if you write the problem out on a peice of papaer it will make sense

kirill [66]3 years ago
3 0

Answer:

its 42 the other answer is wrong

Step-by-step explanation:

First calculate how long it will take one person to paint one wall.

Hint #22 / 5

It will take \dfrac{1}{4}  

4

1

​  start fraction, 1, divided by, 4, end fraction of the time to paint one wall. So it will take 888 minutes for 333 people to paint one wall.

Hint #33 / 5

For only one person, it will take 333 times as long, so it will take 8 \cdot 3 = 248⋅3=248, dot, 3, equals, 24 minutes for one person to paint one wall.

Hint #44 / 5

So, the number of minutes it will take for one person to paint 777 walls is 24 \cdot 7 = 16824⋅7=16824, dot, 7, equals, 168.

Hint #55 / 5

The number of minutes it will take for 444 people to paint 777 walls is 168 \div 4 = 42168÷4=42

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Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
True or false ? help plz
shutvik [7]

Answer:

TRUE

Step-by-step explanation:

5 0
3 years ago
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Iteru [2.4K]

Step-by-step explanation:

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Square both sides of the equation.

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6 0
2 years ago
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blagie [28]
32 40%
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6 0
2 years ago
Six yards of rope costs $5.50 while four yards costs $4.75
Amiraneli [1.4K]

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<u>Step-by-step explanation:</u>

For the given question case, first we should compare the unit costs of the choices provided and evaluate the best option.

Choice 1:

Six yards of rope costs $ 5.50

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Thus, the best choice is the first one. Because it is the lowest unit cost.

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