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algol [13]
3 years ago
6

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

θ? Make sure to show all work.

Mathematics
1 answer:
mixer [17]3 years ago
6 0
Notice the picture below

x = 1 and y = -1

now... recall your SOH CAH TOA   \bf sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}

now.. what's the value for "r" or the radius? well, using the pythagorean theorem \bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad 
\begin{cases}
a=x\\
b=y\\
c=r
\end{cases}

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You roll a six sided die. What is the probability of rolling a 1 or a number greater than 4.
Romashka [77]

A. 1/2

This is because there are 6 possible outcomes. 1, 2, 3, 4, 5, and 6.

The probability of rolling 1, 5, and 6 is 3 out of 6 (3/6)

3/6 reduced is 1/2.

3 0
3 years ago
(5 + 7) x 5³ pleaseeeeeeeeee help
nekit [7.7K]

Answer:

1500

Step-by-step explanation:

6 0
3 years ago
What is the sum of ten terms of an infinite geometric series if the first term is 8 and the ratio is 1/2
xxTIMURxx [149]

Answer:

We use the formula:

S 10 = 8 · [(1/2)^9 - 1] / (1/2 - 1 );

Then, S 10 = 8 · ( 1/512 - 1 ) / ( 1/2 - 1 );

S 10 = 8 · ( - 511 / 512 ) / (-1 / 2 );

S 10 = ( - 511 / 64 ) · ( - 2 );

S 10 = + 511 / 32;

S 10 = 15.96;

Step-by-step explanation:


6 0
3 years ago
Complete the equation of the line through (-10,-7)(-5,−9)
Igoryamba
Slope
-9+7 -2
—— = ——
-5+10 5

Equation of a line
y+7=-2/5(x+10)
y+7=-2/5x-4
y=-2/5x-11
8 0
2 years ago
Simplify the following expression.<br><br> 7d + 12 – 4d – 3
Stella [2.4K]

Hello!

7d + 12 -4d -3\\

Explanation:

↓↓↓↓↓↓↓↓↓↓↓

First this problem it should be the group like terms.

7d-4d+12-3

Then you add similar elements.

7d-4d=3d

3d+12-3

You can also add or subtract by the numbers.

12-3=9

=3d+9

Answer⇒⇒⇒3d+9

Hope this helps!

Thank you for posting your question at here on Brainly.

Have a great day!

-Charlie

3 0
3 years ago
Read 2 more answers
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