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algol [13]
3 years ago
6

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

θ? Make sure to show all work.

Mathematics
1 answer:
mixer [17]3 years ago
6 0
Notice the picture below

x = 1 and y = -1

now... recall your SOH CAH TOA   \bf sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}

now.. what's the value for "r" or the radius? well, using the pythagorean theorem \bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad 
\begin{cases}
a=x\\
b=y\\
c=r
\end{cases}

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What is the solution to this equation?<br> X- 17 = -5
Nitella [24]
X=12

-5+17=12 - this is the quickest way to solve an easy equation like this
7 0
2 years ago
What is a solution to the system of equations that includes quadratic function f(x) and linear function g(x)? f(x) = 2x2 + x + 4
olga_2 [115]

The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is

(\sqrt{2},\sqrt{-2}  ) and ((7+\sqrt{2)} ,(7+\sqrt{-2}))

We have given that,

f(x) = 2x^2 + x + 4

x                          g(x)      

-2                               1      

  -1                              3        

  0                              5      

  1                              7

  2                              9

<h3>What is a polynomial function?</h3>

A polynomial function is a relation where a dependent variable is equal to a  polynomial expression.

A polynomial expression is an expression including numbers and variables, where variables are raised to non-negative powers.

The general form of a polynomial expression is:

a₀ + a₁x + a₂x² + a₃x³ + ... + anxⁿ.

The highest power to a variable is the degree of the polynomial expression. When degree = 2, the function is a quadratic function.

When degree = 1, the function is a linear function.

<h3>How do we solve the given question?</h3>

The quadratic function is given to us:f(x) = 2x^2 + x + 4.

We need to determine the linear equation g(x).

Since it's a linear equation we use the two-point method to determine the equation.

<h3>What is the two-point?</h3>

y-y₁ = ((y₂-y₁)/(x₂-x₁))*(x-x₁)

We take the points g(-2) =1, g(-1) = 3

g(x) - g(1) = ((g(-2)-g(-1))/(-2+1))*(x-1)or,

g(x) - 1 = ((-2-(-1))/(-2+1))*(x-1)or, g(x) - 1 = -1(-x+1)or,

g(x) = x - 1 + 1 = x

∴ g(x) = x , is the linear function g(x)

We are asked to find the solution to the system of equations f(x) and g(x).To find the solution we need to check what is the common solution to both f(x) and g(x).

For that, we equate f(x) and g(x).2x^2 + x + 4 = x or, 2x² - x +x- 4 = 0or, 2x^2  - 4 = 02(x^2-2)=0x^2-2=0x^2-\sqrt{2}=0(x-\sqrt{2}) (x+\sqrt{2})=0(x-\sqrt{2})=0 \\x=\sqrt{2}  or x=-\sqrt{2}g(-1) = 3(from the table)g(\sqrt{2})=\sqrt{2}  \ and \ g(\sqrt{-2}) =-\sqrt{2}f(\sqrt{2}) = 2(\sqrt{2} )^2 + (\sqrt{2} ) + 3\\=2(2)+\sqrt{2} +3\\=7+\sqrt{2}g(-\sqrt{2} )= 2(\sqrt{-2} )^2 + (\sqrt{-2} ) + 3\\=2(2)+\sqrt{-2} +3\\=7+\sqrt{-2}

The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is (\sqrt{2},\sqrt{-2}  ) and ((7+\sqrt{2)} ,(7+\sqrt{-2}))

Learn more about linear and  quadratic equations at

brainly.com/question/14075672

#SPJ1

5 0
2 years ago
Has one negative and one positive coefficient Simplifies to 5x + 12​
rosijanka [135]

Answer:

Step-by-step explanation:

whats the question here lol

8 0
3 years ago
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nikitadnepr [17]

Answer:

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And in some cases there may be the use of pythagoras theorem

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3 years ago
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a) Everyone on the team talks until the entire team agrees on one decision. O b) Everyone on the team discusses options and then
insens350 [35]

Answer:

a) Everyone on the team talks until the entire team agrees on one decision.

Step-by-step explanation:

Option B consists of voting and not everyone would like the outcome. Option C is making an outsider the decision maker, which can't be helpful since he / she won't have as strong opinions as the team itself. Option D is just plain wrong as it defeats the purpose of team work and deciding as one team. So, I believe option A makes the most sense

8 0
3 years ago
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