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3 years ago

Which of the following is the solution to lx-13 k 18 ?

Mathematics

1 answer:

natali 33 [55]3 years ago

7 0

I think d is the answer

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Solve for r. -13 = r/9 +8

love history [14]

R/9 = -21
Multiply by 9
r = -189

4 0

2 years ago

Read 2 more answers

Can someone pls help need it ASAP and can you pls explain in full detail how to do it

GenaCL600 [577]

Answer:

x= 1 , y=4

Step-by-step explanation:

x-y= -3 => Equation 1

x+5y= 21 => Equation 2

Substitution Method:

Substitute Equation 1=>

x=y-3 <= Equation 3

Put x=y-3 in Equation 2:

x+5y=21

( y-3)+5y=21

y-3+5y=21

6y-3=21

6y=21+3

6y=24

y=24÷6

y=4

Put y=4 in Equation 1:

x-y= -3

x-4=-3

x=4-3

x=1

Hope this helps :)

8 0

3 years ago

Read 2 more answers

Which equation is the equivalent form of 20(3)^5x = 820?

makvit [3.9K]

Answer:

x=ln(41)/ln(243)

Step-by-step explanation:

20(3)^5x=820

3^5x=820/20

3^5x=41

5x=ln(41)/ln(3)

x=(1/5)[ln(41)/ln(3)]

x=ln(41)/ln(3^5)

x=ln(41)/ln(243)

8 0

3 years ago

Irma needs to rent a car for a business trip from Phoenix to San Jose (720 miles one way). She will drive round trip and will be

cricket20 [7]

The cost per day is $65 per day, the total cost for 8days will be:
8×65
=520
suppose that E is the number of miles she can drive without exceeding $600.
Thus
0.24×E+520=600
hence solving for E we get
0.24E=600-520
0.24E=80
hence
E=80/0.24
E=333.3333
E~333

8 0

3 years ago

The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F

OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

$\frac{(1 -0.99)}{2}=0.005$

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

$n=\frac{z^2pq}{e^2}$

Where, e is the margin of error,

Substitute the respective values.

$n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89$

Hence, the Sample size is 1918.89035

4 0

3 years ago