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kvv77 [185]
3 years ago
5

Can someone help me with two and three please

Mathematics
1 answer:
joja [24]3 years ago
3 0
 2) The answer is all squares are rectangles. 

3) Not all parallelograms are rectangles.
You might be interested in
Pls help question is on picture
brilliants [131]

Answer:

9/15 = 3/5 (simplified)

Step-by-step explanation:

In a right triangle, the cosine is the ratio of the adjacent side to the hypotenuse:

\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}

The adjacent side is the side that makes up the angle but is not the hypotenuse.

I'm assuming the answer box should ask for cos(theta) rather than cos(x).

5 0
3 years ago
Rhianna says she can draw different functions that have the same x‑intercepts and the same domain and range. Her teammates say,
qwelly [4]

In both cases there are more than one possible function sutisfying given data.

1. If

  • x‑intercepts are (–5, 0), (2, 0), and (6, 0);
  • the domain is –5 ≤ x ≤ 7;
  • the range is –4 ≤ y ≤ 10,

then (see attached diagram for details) you can build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their maximum and minimum left and right you can obtain another function that satisfies the conditions above.

2. If

  • x‑intercepts are (–4, 0) and (2, 0);
  • the domain is all real numbers;
  • the range is y ≥ –8,

then you can also build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their  minimum left and right you can obtain another function that satisfies the conditions above.

Note, that these examples are not unique, you can draw a lot of different graphs of the functions.

Answer: yes, there are more than one possible function

6 0
3 years ago
Delilah finds her answer is 90, but she copied the expression incorrectly from the board. If her reasoning and answer for the ex
USPshnik [31]

Question:

Three students were working on 630,000÷700 in math class.

a. Desiree finds the quotient is 9,000 and Micah finds the quotient is 900.

    Determine which student found the correct quotient.

b. Delilah finds her answer is 90, but she copied the expression incorrectly from the board. If her reasoning and answer for the expression she copied are correct, what expression might she have written?

Answer:

a. Micah is correct

b.

Expression = 63000 \div 700

Expression = 630000 \div 7000

Step-by-step explanation:

Given

Expression = 630000 \div 700

Desiree = 9000

Micah = 900

Solving (a): Who is correct?

To do this, we first calculate the quotient of the expression.

Expression = 630000 \div 700

Divide 630000 by 700

Quotient = 900

Hence:

Micah is correct

Solving (b): What Delilah must have copied?

We have:

Delilah = 90

There are no options to pick from. So, we just need to work out expressions that equals 0.

Possible expressions are:

Expression = 63000 \div 700

Expression = 630000 \div 7000

3 0
3 years ago
Simplify the following
marusya05 [52]

Answer:

try 6^(-1) = 0.17 or 1/6

Step-by-step explanation:

1/6 in decimal form is 1.66666... which technically should round to 1.7

if 1.7 isn't the right answer try righting it in exact form, 1/6 where there is no estimation

7 0
3 years ago
Jenson has 256 beads. He gets 67 more beads from a friend. He then uses 157 of the beads to make necklaces for his teachers. Fin
Murljashka [212]
So Jenson has 256 beads + 67 beads =  323 beads - 157 beads for the <span>necklaces = </span> 166 beads divided by 8 beads per bracelet = 20 bracelets with the remainder of 6 beads.  
8 0
3 years ago
Read 2 more answers
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