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3 years ago

Can someone help me with two and three please

Mathematics

1 answer:

joja [24]3 years ago

3 0

2) The answer is all squares are rectangles.

3) Not all parallelograms are rectangles.

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Please help me with this problem

Snowcat [4.5K]

The answer is -6x + 5y <_ -30

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3 years ago

Write the function f(x) = 3x2 - 6x + 5 in vertex

weeeeeb [17]

3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)

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2 years ago

Giải phương trình sau:<br> sinx=1/2

cupoosta [38]

Answer: $\begin{bmatrix}\mathrm{Radians:}\:&\:x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi n\:\\ \:\mathrm{Degrees:}&\:x=30^{\circ \:}+360^{\circ \:}n,\:x=150^{\circ \:}+360^{\circ \:}n\end{bmatrix}$

Step-by-step explanation:

$\sin \left(x\right)=\frac{1}{2}$

$x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi$

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2 years ago

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Mrs.Wang is 23 years older than her daughter. In 5 years, their ages will total 63. How old are they now

Katena32 [7]

Mrs. Wang is 55 years old and her daughter is 18 years old.

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3 years ago

Read 2 more answers

One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on

irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna = 237.08 ft

Step-by-step explanation:

The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°

distance from her position to the top of the building = 2475 ft

distance from her position to the top of the flag = 2615 ft

(a) How far away from the base of the building is the surveyor located?

using the SOHCAHTOA principle

cos 34° = c/2475

c = 0.8290375726 × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b = 0.5591929035 × 2475

b = 1384.0024361

b = 1384.00 ft

(c) What is the angle of elevation from the surveyor to the top of the antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ = 0.784665392

∅ = cos-1 0.784665392

∅ = 38.310258303

∅ = 38.31°

(d) How tall is the antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) = 0.6199159917 × 2615

(a + b) = 1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00 = 237.08031822 ft

Height of antenna = 237.08 ft

8 0

3 years ago