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andrey2020 [161]
3 years ago
9

3xy - 4y when y = 2 and x = 5​

Mathematics
2 answers:
tia_tia [17]3 years ago
7 0

Answer:

22

Step-by-step explanation:

kupik [55]3 years ago
4 0
The answer is 22!! :) mark me as brainliest please so I can help more people ?!
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If x does not equal 16 then 2x+10 does not equal 42​
Lady bird [3.3K]

Answer:

The answer is

True

5 0
3 years ago
Read 2 more answers
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
Help me on this question please. Thx
lana [24]
The trapezoid was translated Right 6 ,down 5
3 0
2 years ago
What’s 4 and 3/16 + 1 and 1/10 in simplest form?? PLEASE NEED THIS ASSAP pleaseeee
mrs_skeptik [129]
5 and 23/80 is the answer
3 0
3 years ago
Read 2 more answers
PLEASEEEEE HELPPPP ASAPPP
Ivanshal [37]

Answer:

  40.5°

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

In this triangle, that means ...

  tan(x°) = 4.7/5.5

The angle is found using the inverse function:

  x° = arctan(4.7/5.5) ≈ 40.5°

8 0
3 years ago
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