6th grade math help please
2 answers:
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Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that . This formula implies that
.
First, observer that .
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So,
Then, applying 1) we have that
So, Sam Whittingham’s time through the 200 m was 5.5549s.