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3 years ago

What is the probability each player has a winning?

Mathematics

1 answer:

olganol [36]3 years ago

4 0

You have a 1 in 50 chance (ie A)
Explanation:
Let's start with the first bag. In it sits 5 numbers. So, you have a 1 in 5 chance that the number picked will be yours.

Now, let's consider the second bag. You have 10 different numbers and only one of yours may be picked. Hence, you have a 1 in 10 chance that yours will get picked.

Since we want them simultaneously, we will need to multiply the two probabilities together, yielding a 1 in 50 chance.

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HELP PLEASE WORTH 100 Points

Harlamova29_29 [7]

Well it’s ok I just have no problem I don’t have any time to talk to answer A

5 0

2 years ago

Read 2 more answers

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$

The standard deviation of a sample of n young man is given by the following formula

$s = \frac{\sigma}{\sqrt{n}}$

We want to have $s = 0.167$

$0.167 = \frac{2.8}{\sqrt{n}}$

$0.167\sqrt{n} = 2.8$

$\sqrt{n} = \frac{2.8}{0.167}$

$\sqrt{n} = 16.77$

$\sqrt{n}^{2} = 16.77^{2}$

$n = 281.23$

We need a sample of at least 282 young men.

6 0

3 years ago

Plz help I am bad at this

Vikentia [17]

Your answer is either A or D

8 0

2 years ago

Is this relation a function justify your answer

Karo-lina-s [1.5K]

No because there is absolutely no correlation

4 0

3 years ago

Read 2 more answers

A segment with endpoints (5,8) and (-6,8) is rotated around the origin. How long will the new segment be?

Gekata [30.6K]

The segment was only rotated, not changed. It would be the same length as the original.

To find the length, use the distance formula.

$\sqrt{ {(x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$
(5, 8) would be point 1.

(-6,8) would be point 2.

Plug them into the formula.

$\sqrt{( { - 6 - 5)}^{2} + ( {8 - 8)}^{2} }$
Simplify.

$\sqrt{( { - 11)}^{2} + ( {0)}^{2} }$
$\sqrt{121 + 0}$
$\sqrt{121}$
Square root this answer.
$\sqrt{121} = + or - 11$
Negative distances aren't possible, so your answer is 11.

Hope this helped!

:)

5 0

3 years ago