What is the area of the figure?
1 answer:
We can break it into two parts.
-> First, the rectangle on the bottom is made up of 2 feet x 16 feet. The formula for area of a rectangle is length times width, so in this case it is equal to 32 feet
-> Next, the triangle has sides of 10 feet, 10 feet, and 16 feet. We can calculate that the height is 6. The formula for area of a triangle is base times height divided by two, so, 48 feet
-> Last, we can add the two totals together. 32 feet + 48 feet = 80 feet giving us our final answer of 80 feet². As this answer is not pictured I am going to assume they are not including Heron's formula or other more complex formulas, leading us to the answer of "can't be determined"
Answer:
O can't be determined
Have a nice day! - <em>Note: It depends on the level of your math class for whether the answer "cannot be determined" is correct as it can be determined, just takes more effort than simple one - two-step formulas.</em>
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
★ Also please leave the rating you think I deserve (It helps other users as well as myself)
- Heather
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Answer:
Step-by-step explanation:
The formula one would use for finding the volume of a rectangular prism is as follows:
- Volume = length × width × height ,
With this in mind, let's plug in the given variables in the question for this formula.
?
- We don't know the height, but that's just fine. We will plug in all our values and isolate
.
- I'm leaving in units just because I want to show that units aren't just for show. They can be used when in doubt of how to go about your math.
- Notice, that the units on the left side cancel out, leaving only the unit
left next to the solution. In the same way, the units on the right side cancel out too, leaving only
If involving units only confuses you, like it does for me, you can remove them like so, you just need to know what units your solution uses instead of being able to come to the proper units by using math.