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Answer:
The answer to your question is below
Explanation:
1) 0.143g of Mg into atoms
- Look for the atomic number of Magnesium in the Periodic table
Atomic number = 24.31 g
-Use the Avogadro's number to find the number of atoms
24.31g ------------------- 6.023 x 10²³ atoms
0.143 g ----------------- x
x = (0.143 x 6.023 x 10²³) / 24.31
x = 8.613 x 10²² / 24.31
x = 3.54 x 10²¹ atoms
2) 0.101 kg of Ti into atoms
-Look for the atomic number of Titanium in the Periodic table
Atomic number = 47.87 g
-Use the Avogadro's number to find the number of atoms
47.87 g --------------------- 6.023 x 10²³
101 g ---------------------- x
x = (101 x 6.023 x 10²³) / 47.87
x = 6.08x 10²⁵ / 47.87
x = 1.27 x 10²⁴ atoms
Answer:
At a given temperature, a system of particles can be considered as point masses (m) each moving at a certain translational velocity (v). The motion of these particles can be defined in terms of their average translational kinetic energy which is responsible for the heat transfer during molecular collisions and therefore the temperature of the system.
The kinetic temperature T is given in terms of the average translational kinetic energy as:
T = 2/3k(Kinetic energy)
T = 2/3k(1/2*m*v²)
where K = Boltzmann constant
Ans: C) Average translational kinetic energy
Answer:
2 HgO → 2 Hg + O2
Explanation:
Decomposition is when one reactant breaks down into two or more products due to heat, light or electricity
Here mercury (II) oxide goes through thermal decomposition to make mercury and oxygen
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Answer:</h3>
6.25 atoms
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Explanation:</h3>
<u>We are given</u>;
- The half life of Po-218 is 3 minutes
- Initial sample is 200 atom
- Time of decay is 15 minutes
We are required to calculate the remaining mass after decay;
Half life refers to the time taken for original amount of a radioactive sample to decay to a half.
To calculate the remaining mass we use the formula;
N = N₀ × 0.5^n where n is the number of half lives, N is the new amount and N₀ is the original amount.
n = 15 min ÷ 3 min
= 5
Therefore;
New amount = 200 atom × 0.5^5
= 6.25 atoms
Therefore; the amount of the sample that will remain after 15 minutes is 6.25 atoms.