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Stella [2.4K]
2 years ago
7

The half life of Po-218 is three minutes. How much of a 200 atom sample will remain after 15 minutes

Chemistry
1 answer:
MakcuM [25]2 years ago
6 0
<h3>Answer:</h3>

6.25 atoms

<h3>Explanation:</h3>

<u>We are given</u>;

  • The half life of Po-218 is 3 minutes
  • Initial sample is 200 atom
  • Time of decay is 15 minutes

We are required to calculate the remaining mass after decay;

Half life refers to the time taken for original amount of a radioactive sample to decay to a half.

To calculate the remaining mass we use the formula;

N = N₀ × 0.5^n where n is the number of half lives, N is the new amount and N₀ is the original amount.

n = 15 min ÷ 3 min

  = 5

Therefore;

New amount = 200 atom × 0.5^5

                      = 6.25 atoms

Therefore; the amount of the sample that will remain after 15 minutes is 6.25 atoms.

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The following combination of n=3 ; l=1 ; ml=-2 is not allowed. One way to correct this would be by changing the azimuthal quantum number, l and the other way would be to change the magnetic quantum number, m.

<h3>Is the following combination n=3; l=1; ml=-2 allowed or not.? If not, suggest two ways through which it can be corrected.</h3>

The following combination of n=3 ; l=1 ; ml=-2 is not allowed.

There are several rules that need to be followed for assigning electron quantum numbers. They are:

1. Principal quantum number should be 1 ≤ n

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4. Spin quantum number as either -1/2 or +1/2

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If we choose l = 2 then ml would be -2, -1, 0, +1, +2

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