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3 years ago

For an angle _ with the point (5, _12) on its terminating side, what is the value of cosine?

Mathematics

1 answer:

Vlad [161]3 years ago

5 0

Cos θ = adj/hyp = 5/sqrt(5^2 + (-12)^2) = 5/sqrt(25 + 144) = 5/sqrt(169) = 5/13

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A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are defective?

Solution:

Let the random variable X represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = p = 0.03.

A random sample of n = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable X thus follows a Binomial distribution with parameters n = 10 and p = 0.03.

The probability mass function of X is:

$P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...$

Compute the probability that none of the LED light bulbs are defective as follows:

$P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}$

$=1\times 1\times 0.737424\\=0.737424\\\approx 0.7374$

Thus, the probability that none of the LED light bulbs are defective is 0.7374.

6 0

3 years ago

write the set notation of the following Venn-diagram I will mark him or her as the brainliest answer

GalinKa [24]

Answer:

A intersection B complement

4 0

2 years ago

What is the value of -91/5 - 10 + 2/5+ 2(14 1/2-7)

Scorpion4ik [409]

Answer:

Exact Form:

−64/5

Decimal Form:

−12.8

Mixed Number Form:

−12 4/5

Step-by-step explanation:

bc I used a calculator

5 0

3 years ago

Solve This Using The Quadratic Formula: 3x^2+9x-6=0

aivan3 [116]

<h3>Therefore either $x = \frac{-3+\sqrt{17}}{2}$ or, $x = \frac{-3-\sqrt{17}}{2}$ </h3>

Step-by-step explanation:

$3x^2 +9x -6=0$ $x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}$

$\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}$ here a = 3 ,b = 9 and c= -6

$\Leftrightarrow x = \frac{-9\pm\sqrt{153} }{6}$

$\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}$

$\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}$

Therefore either $x = \frac{-3+\sqrt{17}}{2}$ or, $x = \frac{-3-\sqrt{17}}{2}$

4 0

3 years ago

Can some one help me out my grades are bad

Leya [2.2K]

Answer:

Go to the bottom of that problem and click save for later

5 0

2 years ago