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dmitriy555 [2]
3 years ago
5

Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial:

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

\frac{4}{9}b^2 + 0.4bc + 0.09c^2 = \frac{4}{9}b^2 + \frac{4}{10}bc  + \frac{9}{100}c^2 = (\frac{2}{3}b + \frac{3}{10}c)^2

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A person standing 20 feet from a streetlight casts a shadow as shown. How many times taller is the streetlight than the person?
Xelga [282]

Answer:

2 times taller.

Step-by-step explanation

6 0
3 years ago
Enter in standard form the equation of the line passing through the given point and having the given slope.. . B(2, - 5), m = -2
dalvyx [7]
Y = mx + b
slope(m) = -2/3
(2,-5)...x = 2 and y = -5
now we sub, we r looking for b, the y int
-5 = -2/3(2) + b
-5 = - 4/3 + b
-5 + 4/3 = b
- 15/3 + 4/3 = b
- 11/3 = b

equation is : y = -2/3x - 11/3...but we need it in standard form
Ax + By = C

y = -2/3x - 11/3
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4 0
3 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
Giselle bought a dress for $35 and three t-shirts. She used a coupon for $2.50 off each t-shirt. The total cost can be modeled b
yanalaym [24]
N-2.5 represents the cost for each shirt being subtracted by $2.50 due to the coupon
5 0
3 years ago
Read 2 more answers
Solve the equation 18=n-18<br><br>n=_____​
Maksim231197 [3]

Answer:

36

Step-by-step explanation:

7 0
3 years ago
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