Answer:
=5x2+5x
Step-by-step explanation:
Let's simplify step-by-step.
3x+3x2+2x2+2x
Answer:
The 38th term of 459,450,441,.. will be:
![a_{13}=351](https://tex.z-dn.net/?f=a_%7B13%7D%3D351)
Step-by-step explanation:
Given the sequence
![459,450,441,..](https://tex.z-dn.net/?f=459%2C450%2C441%2C..)
An arithmetic sequence has a constant difference 'd' and is defined by
![a_n=a_1+\left(n-1\right)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%5Cleft%28n-1%5Cright%29d)
computing the differences of all the adjacent terms
![450-459=-9,\:\quad \:441-450=-9](https://tex.z-dn.net/?f=450-459%3D-9%2C%5C%3A%5Cquad%20%5C%3A441-450%3D-9)
so
![d=-9](https://tex.z-dn.net/?f=d%3D-9)
The first element of the sequence is
![a_1=459](https://tex.z-dn.net/?f=a_1%3D459)
so the nth term will be
![a_n=-9\left(n-1\right)+459](https://tex.z-dn.net/?f=a_n%3D-9%5Cleft%28n-1%5Cright%29%2B459)
![a_n=-9n+468](https://tex.z-dn.net/?f=a_n%3D-9n%2B468)
Putting n=38 to find the 38th term
![a_n=-9n+468](https://tex.z-dn.net/?f=a_n%3D-9n%2B468)
![a_{13}=-9\left(13\right)+468](https://tex.z-dn.net/?f=a_%7B13%7D%3D-9%5Cleft%2813%5Cright%29%2B468)
![a_{13}=-117+468](https://tex.z-dn.net/?f=a_%7B13%7D%3D-117%2B468)
![a_{13}=351](https://tex.z-dn.net/?f=a_%7B13%7D%3D351)
Therefore, the 38th term of 459,450,441,.. will be:
![a_{13}=351](https://tex.z-dn.net/?f=a_%7B13%7D%3D351)
39x^3 = 13*3*x*x*x
-6x^2 = 2*3*x*x*-1
-3x = 3*x*-1
so in all these factorizations, 3*x is common. so 3x is the common factor.
by seperating the common factor,
3x(13x^2 - 2x-1)
will be the factorization.
xy + 5x - 5y - 25
=x (y+5) -5 (y+5)
=(x-5) (y+5)
hope I helped ya!!!
Answer:
the answer is c
Step-by-step explanation:
Answer:
Words: three-quarter turn degree: 270° Revolutions: 3/4
Step-by-step explanation:
If this helps you your welcome and if it doesn’t well that what my teachers taught me