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3 years ago

Choose the equation that represents the graph.

Mathematics

1 answer:

sveticcg [70]3 years ago

4 0

Answer:

Answer: Option D

Step-by-step explanation:

Hey there!

From the above question;

The line passes through (-3,0) and (0,3).

Use double point formula;

$( y - y1) = \frac{(y2 - y1)}{(x2 - x1)} (x - x1)$

Keep all values;

$(y - 0) = \frac{(3 - 0)}{(0 - ( - 3))} (x + 3)$

Simplify it;

$y = \frac{3}{3} (x + 3)$

Therefore, y = x+3.

Hope it helps!

You might be interested in

What’s the probability of getting each card out of a deck?

VMariaS [17]

Answer:

a. 1/13

b. 1/52

c. 2/13

d. 1/2

e. 15/26

f. 17/52

g. 1/2

Step-by-step explanation:

a. In a deck of cards, there are 4 suits and each of them has a 7. Therefore, the probability of drawing a 7 is:

P(7) = 4/52 = 1/13

b. There is only one 6 of clubs, therefore, the probability of drawing a 6 of clubs is:

P(6 of clubs) = 1/52

c. There 4 fives (one for each suit) and 4 queens in a deck of cards. Therefore, the probability of drawing a five or a queen is:

P(5 or Q) = P(5) + P(Q)

= 4/52 + 4/52

= 1/13 + 1/13

P(5 or Q) = 2/13

d. There are 2 suits that are black. Each suit has 13 cards. Therefore, there are 26 black cards. The probability of drawing a black card is:

P(B) = 26/52 = 1/2

e. There are 2 suits that are red. Each suit has 13 cards. Therefore, there are 26 red cards. There are 4 jacks. Therefore:

P(R or J) = P(R) + P(J)

= 26/52 + 4/52

= 30/52

P(R or J) = 15/26

f. There are 13 cards in clubs suit and there are 4 aces, therefore:

P(C or A) = P(C) + P(A)

= 13/52 + 4/52

P(C or A) = 17/52

g. There are 13 cards in the diamonds suit and there are 13 in the spades suit, therefore:

P(D or S) = P(D) + P(S)

= 13/52 + 13/52

= 26/52

P(D or S) = 1/2

6 0

3 years ago

Solve for c: c / 3 equals 30 / 5 show your work and apply the correct order of operation

Goshia [24]

Answer:

Unless there is more to the question than c = 2 because 30 /5 = 6 and if c is 3 than 3 = 6 so simplify if needed.

3 0

3 years ago

Read 2 more answers

I hate math bro please help me ill mark u brainliest

yulyashka [42]

Please mark me brainless :)

5 0

3 years ago

You picked two marbles from a bag and record their color. How can you make your selections independent events? Dependent events?

olga55 [171]

Answer:

Let's suppose the next case:

We have a bag, where there are 5 red marbles, and 5 blue marbles.

We have a total of 10 marbles.

Suppose that we pick a marble and we do not replace it, and suppose that the first one is a red marble.

Then now we have in the bag a total of 4 red marbles and 5 blue marbles.

Now let's find the probability of picking a blue marble, this will be equal to the quotient between the number of blue marbles (5) and the total number of marbles (9)

P = 5/9

Now, suppose that instead of a red marble in the first pick, we had a blue marble.

Then now we have 4 blue marbles and 5 red marbles in the bag.

Again, the probability of picking a blue marble will be equal to the quotient between the number of blue marbles (4) and total numbergof marbles (9)

P = 4/9

Then the first pick does affect the probabilities for the second pick, this means that if we do not replace the first marble we pick, then the events will be dependent.

Now, if we replaced the first marble we picked (we put it again in the bag) then the number of blue marbles and red marbles is always the same, then in this case bot events will be independent (the first event will not affect the second event)

4 0

3 years ago

Please help worth a lot of points!!!

V125BC [204]

Let's solve this problem step by step

$2x+3=4(x-6)$ | Given Equation

$2x+3=4x-24$ | Distributive Property of Multiplication over subtraction

$3=2x-24$ | Subtraction Property of Equality

$27=2x$ | Subtraction Property of Equality

$\frac{27}{2}=x$ | Division Property of Equality

Definition of each property:

Distributive Property of Multiplication over subtraction: it says that the product of a number and the difference of two other numbers is equal to the difference between the products of the distributed number.
Subtraction Property of Equality: if the same value is subtracted from two equal sides, the differences remain the same
Division Property of Equality: if the same value is divided from two equal sides, the equation remains the same

Hope that helps!

8 0

2 years ago