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3 years ago

Evaluate 4+(m-n) to the fourth power when m=7 and n=5

Mathematics

1 answer:

Kamila [148]3 years ago

4 0

Answer:

512

Step-by-step explanation:

first you would write it with the other numbers it gives which should look like this: 4+(7-5) then you do the part that is in parentheses 7-5=2 then 4x4x4x4 which equals 256 then you multiply the two together and you should end up with 512

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A triangle has one leg that measures 14 feet and the hypotenuse is 50 feet. What is the length of the other leg?

Aliun [14]

Ok so we are using the Pythagorean theorem so were gonna do A^2 + B^2 = C^2

It don't say which leg we have so you can use either a or b.
Which would get us 14^2 + B^2 = 50^2
14*14 =196 , 50 *50 =2500
Then we have to subtract the two.
So 2500 - 196 = 2,304
Then you take the take the square root of that answer and you have your other leg.
The square root of 2,304 is 48
So the missing leg = 48

8 0

4 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago

Please help me with this.

JulijaS [17]

The speed intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]

<h3>How to determine the range of speed associate to desired gas mileages</h3>

In this question we have a quadratic function of the gas mileage (g), in miles per gallon, in terms of the vehicle speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following quadratic function:

g = 10 + 0.7 · v - 0.01 · v² (1)

An effective approach consists in using a graphing tool, in which a horizontal line (g = 20) is applied on the maximum desired mileage such that we can determine the speed intervals. The speed intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].

To learn more on quadratic functions: brainly.com/question/5975436

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