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2 years ago

Please answer this correctly

Mathematics

1 answer:

Galina-37 [17]2 years ago

6 0

Answer:

1/5

Step-by-step explanation:

The number 5 or greater than 4 is 5.

1 number out of 5 total parts.

= 1/5

P(5 or greater than 4) = 1/5

You might be interested in

Evaluate 3 3/4 ÷ 5/6 =

jeka94

Answer:

9/2 or 4.5

Step-by-step explanation:

15/4x6/5 = 3/2x3 = 9/2

6 0

2 years ago

I provided the answers I just need you to show work. I’ll even mark you the Brainliest!

Sindrei [870]

The intercepts and the graph on your worksheet are not correct. Please see below for details:

$x^2-2x-3=0$ has solutions at x=-1 and x=3 (use the quadratic formula to solve). That means these are the x-intercepts, namely points:

(-1,0) and (3,0).

The y-intercept comes from setting x=0 and calculating the y value:

$y=0^2-2\cdot0-3=-3$

so the y-intercept is (0,-3).

Now to the graph: Based on the form of the function we can see this is a quadratic function and its graph will be a parabola. You can reformat the expression in the following form

$y = x^2-2x-3=(x-1)^2-4$

and that will indicate that the apex of the parabola (open up) will be at the point (1,-4).

Knowing the apex, the x intercepts, and the y intercept, we can graph it now.

Graph is in the image attached.

6 0

2 years ago

-4/3,4/9,-4/27,4/81,-4/243...<br><br> what is the common ratio! HELP ASAP

kaheart [24]

Answer: The common ratio is -1/3

-----------------------------------------------------------

Work Shown:

Pick any term to divide it by the previous term. I'm going to pick the second term and divide it by the first term.

r = common ratio
r = (term 2) divided by (term 1)
r = (4/9) divided by (-4/3)
r = (4/9) * (-3/4)
r = (4*(-3))/(9*4)
r = -12/36
r = -1/3
The common ratio is -1/3

This means you multiply each term by -1/3 to get the next term

For instance
term 2 = r*(term 1)
term 2 = (-1/3)*(-4/3)
term 2 = ((-1)*(-4))/(3*3)
term 2 = 4/9

3 0

3 years ago

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

3 years ago

Read 2 more answers

Please help, this is for 8th grade math.

expeople1 [14]

Answer:

(2,-2)

Step-by-step explanation:

The first step is to substitute y in the first equation with the right side of the second equation because they both equal to y.

-3x+4 = 4x-10

-3x-4x+4-4 = 4x-4x-10-4

-7x = -14

-7x/-7 = -14/-7

x = 2

Plugin 2 for x for either equation to solve for y, I'll be using the second equation, but either one is fine.

y = 4(2)-10

y = 8-10

y = -2

Plugin x = 2 and y = -2 into (x,y), and you get (2,-2)

6 0

3 years ago