Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:
Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:
2. Charlene's rhombus:
Dividing the area calculated, you get:
Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Answer:
15
Step-by-step explanation:
1 dime = 10
1 quarter=25
x=number of coins - dimes
y= number of coins - quarters
x (10)+y(25)=10.25
x+y=50
x= 50-y
x(10)+y(25)=1025
(50-y)(10)+25y =1025
500-10y+25y=1025
500+15y=1025
15y= 1025 - 500
15y=525
y=525/15
y=35
x= 50-35=15
- you will need 2 busses to only transport the boys.
- Mark is at (1 + 5/6) miles of his house.
<h3>How many buses would it take to carry only the boys?</h3>
We know that there are (3 + 1/2) groups, such that each group fill one bus.
2/5 of the students are boys, then the number of groups that we can make only with boys is:
(2/5)*(3 + 1/2) = 6/5 + 1/5 = 7/5 = 5/5 + 2/5 = 1 + 2/5
Then you can make one and a little less than a half of a group, which means that you need 1 and 2/5 of a buss to transport the boys, rounding that to the a whole number, you will need 2 busses to only transport the boys.
<h3>How far is Mark from his house?</h3>
The original distance is:
D = (2 + 3/4) miles.
But Mark only covers 2/3 of that distance, then we have:
d = (2/3)*D = (2/3)*(2 + 3/4) miles = (4/3 + 2/4) miles
d = (4/3 + 1/2) miles = (8/6 + 3/6) miles = (1 + 5/6) miles
Mark is at (1 + 5/6) miles of his house.
If you want to learn more about mixed numbers:
brainly.com/question/21610929
#SPJ1
Answer:
752 below sea level
just took it.
Step-by-step explanation:
We know that:
Mean = 82 mm and SD = 10 mm ( standard deviation )
82 - 3 * SD = 82 - 3 * 10 = 82 - 30 = 52 mm
82 + 3 * SD = 82 + 3 * 10 = 82 + 30 = 112 mm
Population between 52 and 112 mm is within +/- 3 standard deviations from the mean.
By the 66- 95 - 99.7 % rule it is: 99.7% of the test group.
0.977 * 500 = 498.5
Answer:
99.7 % of the test group have a diastolic pressure between 52 and 112 mm, or 498 men.
