Let's divide the shaded region into two areas:
area 1: x = 0 ---> x = 2
ares 2: x = 2 ---> x = 4
In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.
Area 1:

Area 2:





Therefore, the area of the shaded portion of the graph is
A = A1 + A2 = 5.34
If this is a question about who is correct Clair is correct
So, this is kinda similar to the other I helped you with:
<span>So r is the radius of the disk. The area is known and equal to 100Pi; so
100Pi = Pi r2
Now for r: r = 10
Circumference = 2 PI r = 20 Pi
I hope this helped!</span>
8,000,000 pennies equals $80,000. 1/.05=20
20 x $80,000=$1,600,000 more that the bank was able to lend
☺☺☺☺