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Evgen [1.6K]
3 years ago
7

Can you help me please! Graph the Solution set for 3x<-15​

Mathematics
2 answers:
melisa1 [442]3 years ago
7 0
Divide each term by
3 and simplify.

Inequality Form:
x < − 5

Interval Notation:
( − ∞, − 5 )
goldenfox [79]3 years ago
5 0

Answer:

Your answer is: If you solved this inequality you would have to solve the Inequality for x. So your answer would be x < -5, but your graph for that is below ↓

Step-by-step explanation:

Hope this helped : )

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Assured normally costs £42 if you receive a 15% discount how much change will you get from £50
vesna_86 [32]
5% of £42 = £2.10
10% of £42 = £4.20
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3 years ago
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Find the mean 3,4,4,2,5,7,2
stich3 [128]
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Find the smallest positive $n$ such that \begin{align*} n &amp;\equiv 3 \pmod{4}, \\ n &amp;\equiv 2 \pmod{5}, \\ n &amp;\equiv
Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number x such that taking it mod 4, 5, and 7 leaves the desired remainders:

x=3\cdot5\cdot7+4\cdot2\cdot7+4\cdot5\cdot6

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x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod4

so we multiply the first term by 3.

  • Taken mod 5, the first and last terms vanish and we have

x\equiv4\cdot2\cdot7\equiv51\equiv1\pmod5

so we multiply the second term by 2.

  • Taken mod 7, the first two terms vanish and we have

x\equiv4\cdot5\cdot6\equiv120\equiv1\pmod7

so we multiply the last term by 7.

Now,

x=3^2\cdot5\cdot7+4\cdot2^2\cdot7+4\cdot5\cdot6^2=1147

By the CRT, the system of congruences has a general solution

n\equiv1147\pmod{4\cdot5\cdot7}\implies\boxed{n\equiv27\pmod{140}}

or all integers 27+140k, k\in\mathbb Z, the least (and positive) of which is 27.

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Blababa [14]
V is a real number Because v is 1 which will tell you you came from 7 to 8 which was a 1 jump .
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Answer:

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