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4 years ago

HELP

Mathematics

1 answer:

Alex_Xolod [135]4 years ago

8 0

I do believe the answer is D, a money market account.

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In Mary's first math test she scored 87%. The mean and standard deviation for the class were 71% and 18% respectively. In her se

erica [24]

Answer:

Step-by-step explanation:

Since your population are the students in math class, you can use the z-score formula $z=(x-\mu)/\sigma$ in order to comparing the two math test scores. Where $\mu$ is the mean for the class, $\sigma$ is the standars deviation and x is Mary score.

For the first test $\mu=.71 , \sigma=.18,x=.87$ , so , $z_{1} = (.87-.71)/(.18)=.88$ .

For the second test $\mu=.53 , \sigma=.14,x=.66$ , so , $z_{1} = (.66-.53)/(.14)=.93$

Mary do better in the second test, relative to the rest of the class (because $.88 \leq .93$ , it means the second score is nearer to the mean score of the class than the first one )

6 0

4 years ago

Evaluate: 50 + 6(12 + 4) – 82.

Nataly_w [17]

Answer:

Step-by-step explanation:

Follow DMAS formula:

DMAS rule is followed when multiple arithmetic operations are there in a given problem like addition, subtraction, multiplication and division. It tells they should be performed in order of Division, Multiplication, Addition and Subtraction.

=50+6*3 -82

=50+18-82

=68-82

=14

6 0

3 years ago

Read 2 more answers

Martina purchased a prepaid phone card for $20. long distance calls cost 13 cents a minute using this card. Martina used her car

Dima020 [189]

Phone card = $20
You need to minus 17.92 from 20 = $2.08
$2.08 / 0.13 = how many minutes
= 16

7 0

4 years ago

Read 2 more answers

Please help ASAP !!!??

inn [45]

<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Multiply the expressions so they have a denominator of 10

Once you have done this, you can add them

The answer would be option B

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0

4 years ago

A consumer group selected 100 different airplanes at random from each of two large airlines. The mean seat width for the 100 air

Novay_Z [31]

Answer:

Decreasing the sample size decreases the width of the confidence interval.

Step-by-step explanation:

-Let s be the sample standard deviation and $\bar X$ be the sample mean.

#We calculate the 95% confidence interval for the sample size 100 as below:

$\bar X\pm z_{0.05/2}\frac{s}{\sqrt{n}}\\\\\\=\bar X\pm 1.960\times\frac{s}{\sqrt{50}}\\\\\\=\bar X\pm 0.1960s$

#we then calculate the confidence interval of sample size =50 and of similar mean and standard deviation:

$\bar X\pm z\frac{s}{\sqrt{n}}\\\\\\=\bar X\pm z_{0.05/2}\times\frac{s}{\sqrt{n}}\\\\\\=\bar X\pm1.960\times \frac{s}{\sqrt{50}}\\\\\\\\=\bar X\pm0.2772s$

#Notice that the smaller sample(n=50) has a narrower confidence interval.

Hence, decreasing the sample size decreases the width of the confidence interval.

6 0

3 years ago

Read 2 more answers