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3 years ago

13

Find the roots.x^2-8x+7=0

1 answer:

AfilCa [17]3 years ago

8 0

Answer is : X1=1,x2=7

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Thaddeus shakes his head as he pays $12.37 to the clerk for lunch. Complaining to a friend, Thaddeus says, “Do you realize that

atroni [7]

a)

his income must be "x" which is the 100%, and we would know that 0.2% of that is 12.37.

$\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 12.37&0.2 \end{array}\implies \cfrac{x}{12.37}=\cfrac{100}{0.2}\implies 0.2x=1237 \\\\\\ x=\cfrac{1237}{0.2}\implies x=61.85$

b)

his income must be "x" which is the 100%, and we would know that 2% of that is 12.37.

$\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 12.37&2 \end{array}\implies \cfrac{x}{12.37}=\cfrac{100}{2}\implies 2x=1237 \\\\\\ x=\cfrac{1237}{2}\implies x=618.5$

btw he's not making much either way.

7 0

2 years ago

I don’t know this one

torisob [31]

Answer:

3077.2

Step-by-step explanation:

A circle's mass is found by

Pie times R^2

7^2 is 49, times 3.14 is 153.86

then you Multiply 153.86 by 20 which gives you 3077.2

5 0

4 years ago

Read 2 more answers

In hopes of encouraging healthier snacks at school, Zack brought in a tray of carrot sticks and apple slices to share. The tray

Alex787 [66]

Answer:

48% were carrot sticks.

52% were apple slices.

Step-by-step explanation:

Given that:

Total number of snacks in the tray = 25

Number of carrot sticks = 12

Number of apple slices = 25 - 12 = 13

Percent of carrot sticks = $\frac{Number\ of\ carrot\ sticks}{Total\ Number}*100$

Percent of carrot sticks= $\frac{12}{25}*100$

Percent of carrot sticks = 0.48 * 100 = 48%

Percent of apple slices = $\frac{13}{25}*100$

Percent of apple slices = 52%

Hence,

48% were carrot sticks.

52% were apple slices.

6 0

3 years ago

considering the leading term of the polynomial function. what is the end behavior of the graph? describe the end behavior and pr

mario62 [17]

The leading term of polynomial function is the the term contain highest degree so here in the given question leading term is $-3x^5$

and leading coefficient is the coefficient of the term with greatest exponent -3

RULES for End behaviour

we have following four cases

CASE1: Even degree and positive leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow \infty$

$x\rightarrow \infty$ $f(x)\rightarrow \infty$

CASE2: Even degree and negative leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

CASE3: Odd degree and positive leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow \infty$

CASE4: Odd degree and negative leading coefficient

$x\rightarrow -\infty$ $x\rightarrow \infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

Here in the given case we have odd degree and negative leading coefficient

$x\rightarrow -\infty$ $x\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

3 0

3 years ago

Ms. Jenkins stocks a pond with fish. For every 6 bluegill fish, she puts in 1 rock bass fish. Does this ratio mean that Ms. Jenk

snow_tiger [21]

Answer:

Ms. Jenkins puts <u>for every 6</u> bluegill fish <u>one</u> rock bass fish so she puts the number multiple of 7

6 0

3 years ago