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Vadim26 [7]
3 years ago
13

Find the roots.x^2-8x+7=0​

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0
Answer is : X1=1,x2=7
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makkiz [27]

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Step-by-step explanation:

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Can someone please solve 7???
cestrela7 [59]

Answer:

A

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3 0
3 years ago
Read 2 more answers
Pairs that satisfy function y=2x+1
evablogger [386]

Test a pair from each table by substituting their values into the given equation and solving.

A) y = 2x + 1 .......... 2 = 2(0) + 1 .......... 2 ≠ 1

B) y = 2x + 1 .......... 1 = 2(0) + 1 .......... 1 = 1

C) y = 2x + 1 .......... -1 = 2(0) + 1 .......... -1 ≠ 1

D) y = 2x + 1 .......... -2 = 2(0) + 1 .......... -2 ≠ 1


The only pair that satisfied the equation was from answer choice B. Therefore, B is the correct answer.

8 0
3 years ago
the point (2,3) is in the terminal side of an angle theta, in standard position. what are the values of sine, cosine, and tangen
suter [353]
(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13

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8 0
3 years ago
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