Answer:
o your questions about snow: Is it ever too cold to snow? ... No, it can snow even at incredibly cold temperatures as long as there is some source ... area of the United States, see the average snowfall total table for hundreds of ... Seven days? ... Finally, a Winter Weather Advisory is issued for accumulations of snow
Step-by-step explanation:
Answer
<em>length = width + 15</em>
<em>Area = length * width; area is 54 square feet.</em>
<em>Two equations are:</em>
<em>L = W + 15</em>
<em>L * W = 54</em>
<em>To solve, we substitute first equation into second equation:</em>
<em>(W + 15) * W = 54</em>
<em>w^2 + 15w = 54</em>
<em>w^2 + 15w - 54 = 0</em>
<em>(w+18)(w-3) = 0</em>
<em>w = -18 or 3</em>
<em>The width cannot be negative, so 3 is the width and since length is 15 more than width, length is 18:</em>
<em />
<em>Length = 18 feet</em>
<em>Width = 3 feet</em>
<em />
<em />
<u>Answer</u>
√7 × √5
√3 × √2
<u>Explanation</u>
√9*√16 = 3 × 4
= 12
= 12/1 ⇒ It is a rational answer.
√7*√5 = √(7×5)
= √35
= 5.916079783.... ⇒ Irrational
√3*√2 = √(3×2)
= √6
= 2.449489743... ⇒ Irrational
4√2*√2 = 4 × √(2×2)
= 4 × √4
= 4 × 2
= 8
= 8/1 ⇒ It is rational
The expressions that would give irrational answers are: √7*√5 and√3*√2
1/3(6x-12y)
2x - 4y
the answer is A
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
__
We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
