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pickupchik [31]
3 years ago
9

Find the number that belongs in the green box. Round your answer to the nearest tenth.

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer:

1.2 (to one tenth)

Step-by-step explanation:

Hope that helps :-)

allsm [11]3 years ago
6 0

Answer:

Step-by-step explanation:

Remark

You are going to have to find the angle on the lower right before you can get the answer. Call the angle on the lower right = x

Equation

Sin(60)/7 = sin(x) / 3

Solution

3 * sin(60) / 7 = sin(x)

Sin(60) = 0.866

3*0.866 / 7 = sin(x)

sin(x) = 0.3712

x = sin-1(0.3712)

x = 21.79

Now calculate the 3rd angle call it y

y + 21.79 + 60 = 180

y + 81.79 = 180

y = 180 - 81.79

y = 98.21

Now use the sin law again.

Let ? = z

z/sin(98.21) = 7/sin(60)              Multiply both sides by sin(98.21)

z = 7 * sin(98.21) / sin(60)

z = 6.9282 / sin(60)

z = 8

? = 8

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Help me class8 (surds)​
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Answer:

  • \cfrac{991\sqrt{2} }{80}

Step-by-step explanation:

For a start simplify each of the roots:

  • \sqrt{72} =\sqrt{36*2} =6\sqrt{2}
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Now simplify the expression in steps:

\sqrt{72}-\cfrac{48}{\sqrt{50} }  -\cfrac{45}{\sqrt{128} }  +2\sqrt{98} =

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6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} }  +14\sqrt{2} =

20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =

20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =

20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =

\sqrt{2} (20-7\cfrac{49}{80} )=

\sqrt{2} *12\cfrac{31}{80} =

\cfrac{991\sqrt{2} }{80}

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