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rusak2 [61]
3 years ago
10

Consider a standard deck of 52 playing cards with 4 suits.

Mathematics
2 answers:
Zanzabum3 years ago
8 0

Answer:

3/26

Step-by-step explanation:

In a deck of 52 cards, there are two red suits: Diamonds and Hearts

There are 6 red face cards:

2 red King

2 red Queen

2 red Jack

P(red face card) = 6/52 = 3/26

Lorico [155]3 years ago
6 0

Answer:

3/26

Step-by-step explanation:

The face cards are: Jack, Queen, and King. There are only three face cards for each of the 4 suits.

Among the 4 suits, two of them are red: diamonds and hearts. And, each of these two has 3 faces. That means that in a deck of 52 cards, there are 2 * 3 = 6 cards that are both red cards and face cards.

Probability is (# times specific event can occur) / (# times any general event will occur).

Here, the specific event is drawing a card that is both red and a face card (of which there are 6 ways), and the general event is drawing a card (of which there are 52 ways):

P(draw a card that is both red and a face card) = 6/52 = 3/26

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6 0
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5 0
4 years ago
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Tomtit [17]
To solve the question we use the following analogy:
Given that the odds of winning is a/b, then the probability is b/(a+b)
hence to solve the question we proceed as follows:

a]
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odds against E=(36-11)/11
simplifying this gives us:
25/11

b] P(E)=31/36
odds against E=(36-31)/31
simplifying this we get:
5/31
hence odds in favor of E=31/5


c]P(E)=32/36
odds in favor of E will be:
36/(36-32)
simplifying the above we get:
36/4
=9/1

d]
P(E)=30/36
odds against E will be:
(36-30)/36
simplifying this we obtain:
6/36
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e] P(E)=13/36
odds against E will be:
(36-13)/13
simplifying this we obtain:
23/13



6 0
4 years ago
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